Recent content by Jacob87411

  1. J

    Troubleshooting Mass Flow Rates for CH4 Reaction with Air and Fuel

    Ok this is what I got (I really appreciate the help by the way): CO2=44 g/mole H2O=18 g/mole O2=32 g/mole N2=28 g/mole Total mass of exhaust=565/12 massfractionCO2=.077 massfractionH2O=.064 massfractionO2=.113 massfractioN2=.745 Mass flow of exhaust=mass flow air + mass flow fuel =...
  2. J

    Troubleshooting Mass Flow Rates for CH4 Reaction with Air and Fuel

    So if I have 25 kg/s of air and air is 21% O2 I have (.21*25kg/s) gives kg/s of O2. Then (.21*25 kg/s)/32 = N_O2? Similarly ((.79*25kg/s)(3.76N2))/28 gives N_N2 How would it work for CO2 for example? Do I find the amount of moles of C, then use the fact that 25% of the moles of oxygen are...
  3. J

    Troubleshooting Mass Flow Rates for CH4 Reaction with Air and Fuel

    I have this reaction: CH4+4(O2+3.76) --> CO2+2H2O+2O2+15.04N2 Through other calculations and given information I have found that the mass flow rate of the air (the O2+3.76N2) is 25kg/s and the mass flow rate of the fuel is .87 kg/s. I am having the hardest time finding, using these mass...
  4. J

    What Are the Products of Acetylene Combustion in Air?

    Well my question wasn't with balancing it, I just wanted to confirm what the product were, not how much of each. So CO2, H20 and N2 are the products?
  5. J

    What Are the Products of Acetylene Combustion in Air?

    Acetylene (C2H2) is burned with a stoichiometric amount of air during a combustion procss. Assuming complete combustion, determine the air-fiel ratio on a mass and mole basis. I'm not asking for help on the actual question I just don't know what the basic chemical equation is? C2H2 +...
  6. J

    Very basic current direction question

    So it only flows through one pair of the capacitors, not both?
  7. J

    Very basic current direction question

    Yes they are supposed to be connected...so once you combine the parallel sets on either side and reduce it to two capacitors are those capacitors in parallel or series
  8. J

    Very basic current direction question

    I attached a picture..Im just curious, if your calculating the capacitance on each plate why is the answer .5 if the V=1000 and each capacitor plate is 500 microfarads.. If C=500 for each plate then first you have two sets of parallel plates so it simples to a series with two plates of 1000...
  9. J

    Mass Flow Rate Through 40 cm Tube at 18 m/s

    If I know air is flowing through a tube with diameter of 40 cm at 18 m/s, with P=1 atm, T=32 C how do I find the mass flow rate..thank you
  10. J

    How Do You Calculate the Mass of Each Gas Component in a Heated Mixture?

    1. A mixture at T=300 K and P=100 kPa is made up of .1 oxygen, .2 carbon dioxide, and .7 Nitrogen. It is then heated to 300 kPa and 500 K. Find the mass of each component I originally thought using PV=NRT, ideal gas but there doesn't seem to be enough givens. Can you also find the molar...
  11. J

    Acceleration on an inclined plane

    This is more a general case question than a specific problem. Say you have a box on an inclined plane and you break the forces into the components, sum the forces in Y and X. If you keep your X and Y axis' the way they usually are (don't make the X axis along the inclined plane) and the box is...
  12. J

    Solve Ideal Gas Law Problem: V2 and P2 for Ar and N2 mixture at 400 K

    Yes but I am still confused. How do you use the mole ratio to find the pressure after heating it up
  13. J

    Solve Ideal Gas Law Problem: V2 and P2 for Ar and N2 mixture at 400 K

    V1=V2=23.2 m^3 or you mean the volume of the tank is constant because I thought the 23.2 was thevolume of the gas not the tank
  14. J

    Solve Ideal Gas Law Problem: V2 and P2 for Ar and N2 mixture at 400 K

    1. A rigid tank contains .5 kmol of Ar and 2kmol of N2 at 250 kPa and 280 K. The mixture is now heated to 400 K. Determine the volume of the tank and the final pressure of the mixture. 2. PV=NRT Can you find the initial volume by using PV=NRT? V=NRT/P V=(2.5)(8.314)(280)/250=23.2...
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