Hey, I have a couple of _easy_ questions about hyperbolas, but its been a while since I have worked with them and am not able to look them up in my math book currently...if someone could just get me started in the right direction, I would really appreciate it :)
Given the equation of the...
Ok, thanks for all the help :) One last question...
lim[x->0]1/cosbx I can sub 0 in for x, can't I? Then, since sinb would be multiplied by 0, it would turn out 0, which would make it 1/0, which would be undefined...?
lim[x->0](tanbx/sinbx)
lim[x->0]{(sinbx/cosbx)/sinbx} x cosbx/cosbx
lim[x->0](Sinbx/CosbxSinbx)
if I cross out the two Sinbx, I'm left with 1/cosbx. This doesn't seem to get me anywhere. Is there a theorm that I am missing?
lim[x->0](sin^3(kx)/x^3)
lim[x->0](sin[kx]^3)...
Oh, and, another piecewise one he took off 1 point, not full credit but still I don't know what he didn't like about it...
Define g(x) = (x^2+x-6)\(x+3) as a piecewise function so that it will be continuous everywhere.
My end result was
g(x) = (x-2, x>=0)
(-x+2, x<0)
I have these two limit problems that I tried to solve, but got them wrong, and the teacher didn't point out what was wrong with them. I don't want to do it on a future test obviously, but I can't figure out what I did wrong with them. Can someone help solve these two problems...
Excuse me for being dumb, but I still can't figure it out.
c^2 = 20^2 + (58+x)^2 gives me really hard to work with numbers, I don't think I'm doing it right.
First off, my attached image will make things make sense. I have a triangle (with a 90 degrees corner), I know that the height is 20' and that the length is more than 58'. I need to find out what the length is to the left of the 6' height mark (trying to find the length of the red line). Can...
Hi, I have just one more problem :) here it is:
(because I don't know how to do theta, "@" will equal theta)
Find a value of K so that f(2) is continuous at @=0
( != means "not equal")
f(@) = ( (2sin@)/@ , @ !=0 )
( 5k , @=0 )
f(@) is a piecewise function
I don't know...
Thanks for your help, I just thought of something else, too. Seems like this works and is very easy, could you do just a quick check of it and see if it makes sense?
f(a) = b, g(b) = c, h(c) = d
lim[x->a](h(g(f(a)))) = d
f(a) = b, so g(f(a)) = g(b)
g(b) = c, so h(g(b)) = h(c)
h(c) =...
I'm stuck on one complicated limits problem, wondering if any of you could help me :) usually I am pretty fine with limits but this one uses all variables and has functions in it. Anyways, here it is:
f(a) = b, g(b) = c, h(c) = d
prove lim[x->a](h°g°f)(a) = d
(° = "of")
Can anyone...