It was given to me as part of the question.
My supervisor also mentioned that she created a schema in the database and that should I have write access to it, but I am not sure how that relates to the creation and population of the tables.
This here is the updated question:
Consider the following in a database:
Table 1 should contain the following columns and be named vote_share:
● Riding Number
● Riding Name in English
● Riding Name in French
● Total votes
● Turnout (votes / voters)
● Conservative Vote Share
● Liberal...
I have been asked by my team lead to create two tables for a database and to outline the rationale behind my table design choices.Table 1 should contain the following columns and be named vote_share:
● Riding Number
● Riding Name in English
● Riding Name in French
● Total votes
● Turnout (votes...
But I am not sure how the dependence changes if we have a Euclidean disk (that is, a plane with a boundary).
My intuition is that the ##K(x,y)## now depends not only on the spacetime points ##x## and ##y##, but also on the 'border.' The dependence is such that ##K(x,y)## for the Euclidean disk...
I haven't found a proof of it. I read this in a paper.
This is my understanding of the problem.
The Euclidean plane is a maximally symmetric space with ##3## translation symmetries and ##3## rotation symmetries. Any physical quantity ##K(x,y)## on the Euclidean plane, where ##x## and ##y## are...
I'm not sure if your post is suitable for the homework subforum, but to offer immediate guidance, you have to memorize the fomula for the energy levels and know what ground state, first excited state, etc. means. You also need to know that the ground state corresponds to ##n=0## and what the...
Any physical quantity ##K(t,x,x')## on a maximally symmetric spacetime only depends on the geodesic distance between the points ##x## and ##x'##.
Why is this so?
N.B.:
This statement is different from the statement that
The geodesic distance on any spacetime is invariant under an arbitrary...
The isometry group of the anti-de Sitter spacetime is ##SO(d-1,2)##, which has a total of ##\frac{1}{2}d(d+1)## isometries.
For the three-dimensional anti-de Sitter spacetime, these are ##6## isometries. These isometries have corresponding Killing vectors, which in global coordinates, are given...
If Green's function analysis just leaves a complicated integral, I'd rather skip that approach.
Is there any way this equation looks similar to one of the many PDEs that's already been solved?
Line ##2## is a so-called kinetic term that describes the interaction of the different leptons and quarks amongst themselves. A kinetic term is a term with the derivative ##\partial## or the covariant derivative ##D##.
Line ##4## is a so-called interaction term that describes the interaction of...
This is, in fact, a physics problem. The physics is that the cylinder is a radially cut-off (at radius ##\rho=1##) anti-de sitter cylinder in global coordinates.
Please ignore the following (in italics) if you are not interested. This is just motivation and is just some dense physics that's of...