Recent content by headbang

You are right that i have to use f^{\prime}(x) to find out where f increases and decreases. I still don't understand how to calculate this, to solve the problem.

Have a function f(x)=4x^3-x^4 Found the x values are X -1, 0, 1, 2, 3 , 4, f(Y) -5, 0, 3, 16, 27, 0 i Need to find f^{\prime}(x) and find where it incteases and decreases??f`(x)= 3*4x^2-4x^3=4x^2(3-x) what to Next?

How to calculate with two unknowns. Solve.. 4x-5y=7 3y-2x=1

Or maybe: 2x-x<3+1 x<4

Can somone please help me understand this. maybe a solution with explanation .. \frac{2x-1}{x+3}<1 Maby the NeXT step..?? 2x-1<x+3 Can we use this in the x=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}

\frac{x+2+2y+2+x-2(y+1)}{(x+2)(y+1)} 2y+2+x-2=x+2y Ok?

3x+18=2x+4-6x 3x-2x+6x=4-18 \frac{7x}{7}=\frac{-14}{7} x=-2An other try... Is it ok? And thank you all so much for helping me, trying to get my head around this math.. You are all worth your weight in gold...

Ok hav to be 6.. 2*3 \frac{2*3*x}{2}+6*3=\frac{x*2*2*3}{3}-x*6 3x+18=4x-6x 3x-4x-6x+18= -7x=-18 7x=18 OK ?

Ok have other solve Equations.. \frac{x}{2}+3=\frac{x+2}{3}-x

Can the ansver be: \frac{2+x}{4y} And i stil don't understand how you solved the messy 3rd term..? what i did from where you left me.. \frac{x+2+2y+2+x-y}{(x+2)(y+1)} \frac{4+2x+y}{(8x+2)(y+1)} \frac{2*2+x*x+y}{x*y+2y+y+y+2}

Ok.. What about this one? \frac{1}{y+1}+\frac{2}{x+2}+\frac{\frac{x+2}{y+1}-2}{x+2} this is where I am at: \left(\frac{x+2}{y+1}-2\right)

You are so good.. You solved it even if i can't read and Write the right Expression... :)

Hello, I am having difficulty solving my math problems. Simplify the Expression and show how.. And kalkulate z²+w(2wz)²-(w+4z²-1)w³-(z+w²)(x-w²) And w=2 I know we have many ways doing it, an the more ways i can study, the bether i can understand this..