Ok i think I've got this...
W/Q(hot)=1-(T(cold)/T(hot))
mgh/Q(hot)=1-(T(cold)/T(hot))
Q(hot)=mgh/(1-(T(cold)/T(hot)))
Q(hot)=1.378*10^6J
Is this correct Simon?
Since efficiency is 1-T(cold)/T(hot), the most efficient engine i could get in this system would be:
Eff= 1-(253.25K/393.15K) = 0.3558.
So only 35.58% of Q(hot) would be converted to work, while the rest goes to Q(cold)
Hi Simon
I'm not sure how to calculate the required energy to warm the working fluid as neither mass or the specific heat capacity. I'm assuming that heat from the working fluid @ 120°C would be the source of energy [Q(hot)] for the engine to use as work and the rest is expelled to the cold...
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Sorry for the late reply, many thanks for your input!
Ahhh yes, googled "flywheels", turned out to be some wheel under a car storing energy. Got confused with flywheels being the tyres haha :D
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