Recent content by extreme

Thanks. I was puzzled as to where to find the slope breaks. Once I graphed this out, I saw several linear lines that crossed each other along the graph and it was at these points I calculated Vinst.

I've constructed a d-t graph and the question is, how do I calculate the instantaneous velocity, vinst, for each slope break? How do I find the slope break? Do I calculate it using v=chginx/chgint formed by the tangent line to the point or using the point alone simular to Vavg. I've drawn...

Thank's HallsofIvy! I should have converted joules to kwh's.

I used 165 watts to climb a set of stairs 3m high for 10s(550n*3m/10s). My electric company supplies 1kw for 1hr for 8 cents. If I climbed those stairs for 1 hour how much money would it be worth? I multiplied 165 by 360 divided by 1000 to get 59.4kw's. If I multiply 59.4 by .08 I get $4.75...

equilibrium Thanks for the quick reply.

equilibrium The question "What is the normal force, FN, and what is the tension, T, in the rope? T (at t = 2.54s) = ______. At equilibrium: FN + T – m2 • g = 0. Then FN = _______." This is a timed simulation and at 2.54s the rope tension,T, is 9.789

Need a check on this one please. In an Atwood Machine simulation, m1 is 1.0kg and m2 is 1.1kg. m2 rests on the floor that exerts a normal force, Fn, on m2. when the system is in equalibrium, the tension, T, in the rope at 2.54s is 9.789. If Fn +T- m2*g = 0 then Fn = .991. Is this correct?