Recent content by bigsmile

Thank you.

After it goes into the mud and KE is lost due to friction, is energy still conserved at that point? Initial: 0 + 0 = 0 ( initial PE + initial KE = 0) In the mud: KE (final) + PE(final) = Friction + (- mgh) = 0= KE (initial) + PE (initial)? I am confused on how to use the Conservation of...

Thanks for you feedback. I assume h1 = L ( 1 - cos 25 degrees) . Is that right? I have troubles to find the "V" . I don't think I should use the initial speed 1.2 m/s. Since it is asking for max angle for 2nd half of swing. Beside theta 0, do I need to set up theta 1 , another angle for 2nd...

Homework Statement An amount of work equal to 1.5 J is required to compress the spring in a spring gun. ? Homework Equations Wtotal = change of KE[/B] The Attempt at a Solution W=ΔKE=(1/2)m(Vf² - Vi²) It sounds like the Vf >0 and would be maximum after the spring is compressed hard and...

A 2.00-kg ball has zero kinetic and potential energy. John drops the ball into a 10.0-m-deep well. 1) Just before the ball hits the bottom, the sum of its kinetic and potential energy is: Zero J 2) After the ball comes to a stop in the mud, the sum of its potential and kinetic energy is: -196...

A simple pendulum, 2.0 m in length, is released by a push when the support string is at an angle of 25° from the vertical. If the initial speed of the suspended mass is 1.2 m/s when at the release point, to what maximum angle will it move in the second half of its swing? Let h1 be the...