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A 2.00-kg ball has zero kinetic and potential energy. John drops the ball into a 10.0-m-deep well.
1) Just before the ball hits the bottom, the sum of its kinetic and potential energy is: Zero J
2) After the ball comes to a stop in the mud, the sum of its potential and kinetic energy is: -196 J
On #1, why is "sum of kinetic and potential energy" turns to zero? I just guess it is due to conservation of energy, but I don't know how to use Math to prove it.
I know in theory Sum of all work equals the change of KE. I am not sure how to apply here. Before the ball hits the bottom, it should still have velocity and KE >0,
In addition, I really don't understand why the answer in both #1 and #2 are different. I thought the answer to #2 is also zero too due to conservation of energy. Why is the sum equal to a) a negative 196 instead of +196 and b) final potential energy of -196 J?
I am very confused. Please help.
1) Just before the ball hits the bottom, the sum of its kinetic and potential energy is: Zero J
2) After the ball comes to a stop in the mud, the sum of its potential and kinetic energy is: -196 J
On #1, why is "sum of kinetic and potential energy" turns to zero? I just guess it is due to conservation of energy, but I don't know how to use Math to prove it.
I know in theory Sum of all work equals the change of KE. I am not sure how to apply here. Before the ball hits the bottom, it should still have velocity and KE >0,
In addition, I really don't understand why the answer in both #1 and #2 are different. I thought the answer to #2 is also zero too due to conservation of energy. Why is the sum equal to a) a negative 196 instead of +196 and b) final potential energy of -196 J?
I am very confused. Please help.