That's great, with a,b,c,d, complete,
So onto part e) thanks for the information provided,
I need 143.307 kg of oil per hour (kg/hr)
1 litre of fresh water is 1kg
So 1 litre of this oil is 0.85kg
So,
143.307/0.85 = 168.596 (what units would this be?)
168.596 x £1.85 = 311.90 £ per hour...
So you're saying that,
Steam h = 3018.12 kJ/kg
Fw h = 209.3 kJ/kg
Therefore 3018.12 - 209.3 = 2808.82 kJ/kg
Therefore 2808.82 x 1500
= 4213230 kJ/hr
This seems a very odd figure...
I then assumed for part d,
Boiler efficiency = heat absorbed by steam/heat added by steam
So 0.7 =...
I have attempted something but not being the greatest at steam calculations I have been confused at a probably easy question.
Up to now I have
Steam h = 3018.12 kJ/kg
Fw h = 230 kJ/kg
For a 235 c temperature rise it it
obvious that
3018.12 - 230 = 2788.12 kJ/kg
Then I thought 2788.12...
Homework Statement
See image attached, have completed the parts a and b using steam tables and interpolation and got the answers
a) Wet steam h at 10.5 bar: h = 2378 kj/kg
b) Superheated steam at 10.5 bar @ 285 Degrees Celsius: h = 3018.12 kj/kg
Which I believe to be correct now, parts c,d...
Ah I see my mistake with the answer now, 1050kpa would be 10.5 bar not 1.5 Bar
1.5 bar is 1.5x10^5 pa or n/m^2
Will correct mistake, input correct figures for h and include a better image...
Homework Statement
This is from a practice mechanical science exam for HNC engineering.
See attachment for the question sheet off a practice exam. I have no idea how to do this after the a and b parts and my answers for which are below the question (underlined), any suggestions or solutions...
Little bit stuck with this practice question for my exams, how do they suppose I work out the length of the individual beams or height of the framework without an initial length? Is there a secret way I've never heard of? Any help would be appreciated, it's foundation degree level but probably...