Recent content by atbruick

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    Projectile Motion-Shooting a Ball

    oh opps so just like you calculated y by using sine use cosine to get x. Thank you! I also just tried to find the second part, the distance it hits below the roof; I needed to find t so I used X=Xo+Vxot, 59=0+11t, and got t to be 5.36. Then plugged that into Y=Yo+Vyot-.5at^2, and got...
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    Projectile Motion: Finding Speed and Direction at 1.41 Seconds After Firing

    Well speed is distance traveled/time elapsed. So do we have to use somewhere the equation v^2=vo^2+2a(x-xo) since distance is involved?
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    Projectile Motion-Shooting a Ball

    Homework Statement A ball is shot from the top of a building with an initial velocity of 15 at an angle = 45 above the horizontal. What are the x and y components of the initial velocity? If a nearby building is the same height and 59 m away, how far below the top of the building will the...
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    Projectile Motion: Finding Speed and Direction at 1.41 Seconds After Firing

    Homework Statement A projectile is fired with an initial speed of 65.8 at an angle of 39.6 above the horizontal on a long flat firing range. Determine the speed and direction (angle) of the projectile 1.41 seconds after firing. Homework Equations Vy=Vyinitial-at The Attempt at a...
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    Calculating Maximum Height in Projectile Motion for an Olympic Long Jumper

    Ok, so hoping my calculations for Vy initial are correct, I got 18 m/s, then I tried finding the maximum height and got 20 meters with time as 0.88, which was incorrect. So I thought I should put in time as 0.44 because that is when he will be at maximum height and got 8.9 and that was incorrect...
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    Calculating Maximum Height in Projectile Motion for an Olympic Long Jumper

    Homework Statement An Olympic long jumper is capable of jumping 8.5 m. How high does he goes? (Assuming he lands standing upright). His initial horizontal velocity is 9.7 m/s. Before it asked his height, I found that the time he is in the air is 0.88 seconds. Homework Equations...
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    Finding Time for Package to Reach Sea Level from Ejection?

    oh so it's like solving vectors? by finding the xvector component and yvector component and then using Pythagorean theorem to find the final velocity?
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    Finding Time for Package to Reach Sea Level from Ejection?

    ok thank you, I got a correct time of 12 seconds, then was asked to find the distance from the plane to the island if I wanted to release it so it would land on the island, and got 1390m. Now I'm being asked to find the final speed of the package when it hits the ground. How do you know whether...
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    Solve for Height of Cliff After Diver Jumps Off at 2.2m/s

    zero, because they are not moving either up or down yet, thank you very much!
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    Solve for Height of Cliff After Diver Jumps Off at 2.2m/s

    Homework Statement A diver running 2.2 m/s dives out horizontally from the edge of a vertical cliff and 2.5 s later reaches the water below. How high was the cliff? Homework Equations Y=Yo+Vyo*t-.5gt^2 I have Y as being 0 (the point when they hit the water) and velocity of y at time...
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    Finding Time for Package to Reach Sea Level from Ejection?

    Homework Statement A relief airplane is delivering a food package to a group of people stranded on a very small island. The island is too small for the plane to land on, and the only way to deliver the package is by dropping it. The airplane flies horizontally with constant speed of 260 mph at...
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    Stones being dropped and thrown from building

    Homework Statement A stone is dropped from the roof of a building; 1.90 s after that, a second stone is thrown straight down with an initial speed of 29.0 m/s, and the two stones land at the same time. a. How long did it take the first stone to reach the ground? b. How high is the...
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    Solving for Time: Dropping Package from Helicopter

    My online homework say's that's not correct. I'm also confused on how you derived your equation?
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    Seat Belt constraints in a crashing car

    For the first I got 22 m/s (instead of 80km/h) then divided that by 30*9.80m/s and got 0.075, which is the time it would take to go from 22 m/s to 0 m/s in the crash. Then I found in that time frame a person could travel 1.65, or 1.7 meters. I hope these calculations are right; I entered 1.7...
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