Recent content by Amitayas Banerjee

  1. Amitayas Banerjee

    How does water rise along a glass plate? (surface tension question)

    So, I was studying about general properties of matter and topics like surface tension. I came across the phenomenon of water rising along a glass plate like in the picture. I looked for some mathematical interpretation of this on the internet and in some books. [![enter image description...
  2. Amitayas Banerjee

    What is the angle between the velocity of and the normal to the racket?

    My approach: Let us take two orthogonal axes: x, parallel to the racket's plane and y, perpendicular to it. For the ball to not spin, the components of initial velocities of the racket and the ball along x-axis must be same. Also, as the line of collision is along the normal to the racket's...
  3. Amitayas Banerjee

    What is the Lagrangian, equations of motion for this system?

    Sir, what are the finally correct equations? Are they $$\frac{d}{dt}(\frac{\partial L}{\partial {\dot x}}) - \frac{\partial L}{\partial { x}}=F$$ and $$\frac{d}{dt}(\frac{\partial L}{\partial {\dot y}}) - \frac{\partial L}{\partial { y}}=F$$ ? Please clarify this
  4. Amitayas Banerjee

    What is the Lagrangian, equations of motion for this system?

    Then my second equation of motion is $$ \frac{d}{dt}(\frac{\partial L}{\partial {\dot y}}) - \frac{\partial L}{\partial { y}}=F\cdot \frac{\partial {(x+y)}}{\partial y}$$? Is it correct now?
  5. Amitayas Banerjee

    What is the Lagrangian, equations of motion for this system?

    Is it not $$F\cdot \frac{\partial {(x+y)}}{\partial x}$$ The factor of F becomes 1. Does it not?
  6. Amitayas Banerjee

    What is the Lagrangian, equations of motion for this system?

    Sir, What is the problem if the displacement of m2 depends on both x and y? How can I modify my equations for that? Is there any problem with my generalized force calculation?
  7. Amitayas Banerjee

    What is the Lagrangian, equations of motion for this system?

    <<Moderator's note: Moved from a technical forum, no template.>> Description of the system: The masses m1 and m2 lie on a smooth surface. The masses are attached with a spring of non stretched length l0 and spring constant k. A constant force F is being applied to m2. My coordinates: Left of...
  8. Amitayas Banerjee

    Calculate the impulse of tension

    Should I conserve momentum along the string? But how can I? The string prevents a free movement along it, but I can only conserve momentum along an axis which allows free movement along it.
  9. Amitayas Banerjee

    Calculate the impulse of tension

    I think this is the scene just when the string becomes taut. Should I now break the velocities into orthogonal components? I can not figure out any conservation law to apply. Please help.
  10. Amitayas Banerjee

    Calculate the impulse of tension

    Homework Statement Homework Equations $$ J \space (\text{Impulse})= \Delta (mv) = F \times \Delta (t) $$ The Attempt at a Solution As much I interpreted, we have to calculate the impulse caused by the tension till the relative velocity of approach along the string becomes 0. T to this, I...
  11. Amitayas Banerjee

    Equilibrium Conditions for a Rotating Rod with Two Point Masses

    But, will this force not be balanced by the weight of the rod? Can you show me the correct FBD of the rod?
  12. Amitayas Banerjee

    Equilibrium Conditions for a Rotating Rod with Two Point Masses

    This is a new system. All things are same, only in this case, the rod is attached to an ideal string with very small length. Here, the tension acts on the rod parallel to it(along it, to be more specific). So, no force acts along the α axis, and my math works here, does it not?
  13. Amitayas Banerjee

    Equilibrium Conditions for a Rotating Rod with Two Point Masses

    What is meant by unknown force from hinge? And why will it not be there while considering torque?
  14. Amitayas Banerjee

    Equilibrium Conditions for a Rotating Rod with Two Point Masses

    I did not write my post #9 based on your #8. My α axis is on the plane and not normal to it and perpendicular to the rod. And I balance forces along this axis on the COM.
  15. Amitayas Banerjee

    Equilibrium Conditions for a Rotating Rod with Two Point Masses

    I have marked both the masses along with the center of mass of the rod. α axis is an axis defined by me as shown in the diagram. It is perpendicular to the rod. Now, my question is, if we balance the forces on the COM along the axis and ensure that there is no movement of the COM along the α...
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