Hi, yes I've done that, I need to know what values of WT to use. But actually you said I don't need to use WT as I used a coefficient. I will send you my answer by pm.
Homework Statement
Question attached.
I want to check what values of WT I should use.
Homework Equations
Effective dose = WT*WR*WT,R
The Attempt at a Solution
For the neutron whole-body dose I have WT = 1.
For the ingested 90Sr and 131I, I also have WT = 1. Are these correct or does...
I'm trying to finish an assignment which is to help me in my exam, but I am very stuck on three questions.
If I find out how to answer question 7, will I be able to answer 8 and 9? I really need a good resource.
Quesitons attached below.
I would like your help if possible. I haven't covered this material.
I have been recommended the following book, do you know if it will cover this material?
Radiation Detection and Measurement (3rd Edition) Glenn F Knoll (Wiley)
Thanks
Homework Statement
I have data for the count rate (of gamma rays) against the thickness of various materials (Al, Pb, Fe etc...).
I want to work out the linear attenuation coefficient. Can I do this by plotting the natural log of count rate against thickness? I don't have values for...
I've attached the question below. I think it means electrons of a few MeV. My reasoning is that Bremsstrahlung doesn't have much of an effect at a few MeV, so both the electron and proton will penetrate the same distance. But I'm not sure...
Homework Statement
Which, of an electron and a proton (of a few Mev), is more likely to penetrate further into matter if they both have:
a) The same energy
b) The same speed
Homework Equations
Bethe-Bloch formula.
Total stopping power = collision loss + radiation loss
(de/dx)t = (de/dx)c +...
Homework Statement
I have attached the question below.
Homework Equations
I'm not sure how to answer the question.
The Attempt at a Solution
[/B]
I started by calculating the specific dose rates for each isotope, but I cannot get any data for 90Sr using...
Right so 6.00000E-01 cm2g-1 x 11.34 gcm-3 gives ~ 1.4 cm-1 for u. When I put all of this into my formula I get 28.98cm which is apporoximately 30cm. I'm satisfied that this is the correct answer unless anyone thinks my value of u is incorrect?