It seemed right because I calculated 26.14 in-lbf as the energy delivered by the Rubberband.
I converted 26.14 in-lbf to 2.1783 ft-lbf by dividing by 12.
Horizontal Velocity:
VH=\sqrt{(\frac{2(2.1783)ft-lbf}{27.999g})[\frac{453.6g}{1lbm}][32.2\frac{lbm-ft}{lbf-s2}]}
Comes out to...
I talked to my engineering teacher and he said I was going about it the wrong way.
I need, at least, 50% Lift. So I reworked my equation and came out with
FL=\frac{(.76764)(.076\frac{lbm}{ft^2})(56.55 in^2)(\frac{47.67\frac{ft}{s}^2}{2})[\frac{ft^2}{144 in^2}]}{[32.2\frac{lbm-ft}{lbf-s^2}]}
I...
I am stumped on how to convert my units for the equation for Force of Lift.
FL=CLPA\frac{v^{2}}{2}
My equation comes out to:
FL=(.76764)(.076\frac{lbm}{ft})(\frac{(65.899\frac{ft}{s})^{2}}{2})
Still figuring out this equation hypertext stuff. Please help if you can.
I am supposed to...
I found the equation for Horizontal Velocity. Here it is for anyone else who might be stuck in the same place.
VH=\sqrt{\frac{2E}{m}}
E is energy
m is mass
In my case Energy was elasticity since my glider was flung from a rubber band. So I had to find ft-lbf, then use different conversion...
I am working on my semester project and have come across a hitch. I am trying to find the Lift Force of my wing using the following equation
FL=CL P A (v2/2)
Where:
FL is Lift Force
CL is Coefficient of Lift (I think)
P is the density of the fluid (Air)
A is the Area
V is Velocity...