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Homework Statement
A short current element dl⃗ =(0.500mm)j^carries a current of 8.90A in the same direction asdl⃗ . Point P is located at r⃗ =(−0.730m)i^+(0.390m)k^.
Find the magnetic field at P produced by this current element.
Enter the x, y, and z components of the magnetic field separated by commas.2. Homework Equations
For a wire : dB = (μ naught/ 4π) (I) (dL X r→) / (r^2)
The Attempt at a Solution
dL = .0005 meters in the j→ direction
I = 8.9 amps in j→ direction
point P is located at r→ = -.730 meters i→ + .390 meters k→
so r is the magnitude of the distance between the point and the wire, so r = .73^2 + .39^2 = .685
μ naught / 4 pi = 10^-7 / 4 pi = 7.95 * 10^-9
Now I'm not sure what to do exactly. I know the cross product of dl and r→ is the determinant, and I know how to do that. Doing that I get a result of .000195 i + .000365 k.
Now do I take (7.95*10 ^-9) * (8.9 amps) (either .000195 or .000365) / (.685 meter^2) to find the i(x) and k(z) components of dB respectively? I've tried things like that and I couldn't get the right answer.
Note: I always do my calculations in standard units like meters and tesla first then convert at the end so I don't confuse myself so I don't think that was my mistake. I think I'm just not understanding what term actually means what in the equation, or how to work with vectors correctly. A nudge in the right direction would be appreciated, thanks for any and all advice.The correct answer is dBx, dBy, dBz = .306, 0 ,573 nT