Volume of linear transformations of Jordan domain

In summary: A)| times the volume of the original domain.In part (5), we are asking whether this is still true if we do not assume T is invertible. In this case, the determinant of T will be 0, and thus the volume of the transformed Jordan domain will also be 0. Therefore, we cannot apply the same reasoning as in part (4) and the statement is not true in this case.Finally, in part (6), we are considering an affine transformation f, which is essentially a combination of a linear transformation (represented by the derivative A=Df(x)) and a translation. The volume of a transformed Jordan domain under an affine transformation will simply be equal to the volume of the original domain multiplied by the
  • #1
ianchenmu
10
0

Homework Statement



Let [itex]T:\mathbb{R}^n\rightarrow\mathbb{R}^n[/itex] be a linear transformation and [itex]R\in \mathbb{R}^n[/itex] be a rectangle.
Prove:








(1) Let [itex]e_1,...,e_n[/itex] be the standard basis vectors of [itex]\mathbb{R}^n[/itex] (i.e. the columns of the identity matrix). A permutation matrix [itex]A[/itex] is a matrix whose columns are [itex]e_{\pi(i)}[/itex], [itex]i=1,...,n[/itex], where [itex]\pi[/itex] is a permutation of the set [itex]\left \{ 1,...,n \right \}[/itex]. If [itex]T(x)=Ax[/itex], then [itex]Vol(T(R))=|R|[/itex].




(2) let [itex]A=I+B[/itex] be an [itex]n\times n[/itex] matrix where [itex]B[/itex] has exactly one non-zero entry [itex]s=B_{i,j}[/itex] with [itex]i\neq j[/itex]. If [itex]T(x)=Ax[/itex], show that [itex]Vol(T(R))=|R|[/itex].




(3) Recall that a matrix [itex]A[/itex] is elementary if [itex]A[/itex] is a permutation matrix as in (1), or[itex]A=I+B[/itex] as in (2), or [itex]A[/itex] is diagonal with all but one diagonal entry equal to [itex]1[/itex]. Deduce that if [itex]T(x)=Ax[/itex] and [itex]A[/itex] is an elementary matrix, then for any Jordan domain [itex]E\subset\mathbb{R}^n[/itex], [itex]Vol(T(E))=|det(A)|Vol(E)[/itex].




(4) Recall from linear algebra (row reduction), that any invertible [itex]n\times n[/itex] matrix [itex]A[/itex] is a product of elementary matrices. Prove that for any Jordan domain [itex]E\subset\mathbb{R}^n[/itex], [itex]Vol(T(E))=|det(A)|Vol(E)[/itex], where [itex]T(x)=Ax[/itex] is invertible.




(5) Is (4) true if we do not assume [itex]T[/itex] is invertible?




(6) Prove: If [itex]f: \mathbb{R}^n\rightarrow\mathbb{R}^n[/itex] is an affine transformation and [itex]E\subset\mathbb{R}^n[/itex] is a Jordan domain, then [itex]Vol(f(E))=|det(A)|Vol(E)[/itex] where [itex]A=Df(x)[/itex] is the derivative of [itex]f[/itex] at some point [itex]x[/itex].




Homework Equations



n/a

The Attempt at a Solution


(1) and (2)are easy but I have little ideas about the rest. What's the volume of a Jordan domain and what's the relationship between [itex]Vol(R)[/itex] and [itex]Vol(E)[/itex]? Why for rectangle [itex]Vol(T(R))=R[/itex] but for Jordan domain, [itex]Vol(T(E))=|det(A)|Vol(E)[/itex]? Thank you.
 
Last edited:
Physics news on Phys.org
  • #2



Hi there, thank you for your post. It seems like you are struggling with some of the concepts in this problem. Let me try to clarify some things for you.

Firstly, the volume of a Jordan domain is a concept from multivariable calculus. Essentially, it is the measure of the space enclosed by the boundary of the domain. For example, in two dimensions, the volume of a rectangle is simply its length multiplied by its width. In higher dimensions, it becomes more complicated, but the basic idea is the same.

In part (1), we are considering a linear transformation T that is represented by a permutation matrix A. This means that the columns of A are simply reordering the standard basis vectors e_1,...,e_n. Since A is a permutation matrix, its determinant is either 1 or -1. Therefore, the volume of the transformed rectangle T(R) is simply equal to the volume of R multiplied by the determinant of A, which is just |R|.

In part (2), we are considering a transformation T represented by a matrix A=I+B, where B has exactly one non-zero entry. This means that T is essentially just a shear transformation in one direction. Again, the volume of the transformed rectangle T(R) is equal to the volume of R multiplied by the determinant of A, which is just |R|.

In part (3), we are considering an elementary matrix A, which is either a permutation matrix, a matrix of the form I+B, or a diagonal matrix with all but one diagonal entry equal to 1. In this case, we can see that the determinant of A is simply equal to the determinant of the non-identity matrix B, which is just the single non-zero entry s. Therefore, the volume of the transformed Jordan domain T(E) is equal to the volume of E multiplied by the determinant of A, which is just |det(A)|.

In part (4), we are considering any invertible matrix A, which can be decomposed into a product of elementary matrices. Since we have already proven that the volume of a transformed Jordan domain is equal to the volume of the original domain multiplied by the determinant of the transformation matrix, we can simply apply this to each elementary matrix in the decomposition of A. Since each elementary matrix has a determinant of either 1 or -1, the overall determinant of A will be |det(A)|, and thus the volume of the transformed Jordan domain will be
 

Related to Volume of linear transformations of Jordan domain

1. What is the definition of a Jordan domain?

A Jordan domain is a subset of n-dimensional Euclidean space that is bounded by a finite number of piecewise smooth hypersurfaces.

2. How is the volume of a linear transformation of a Jordan domain calculated?

The volume of a linear transformation of a Jordan domain can be calculated by taking the determinant of the transformation matrix and multiplying it by the volume of the original domain.

3. What is the significance of calculating the volume of linear transformations of Jordan domains?

Calculating the volume of linear transformations of Jordan domains is important in various fields of mathematics, such as differential geometry and complex analysis. It helps in the study of geometric and analytical properties of these transformations.

4. Are there any specific properties of Jordan domains that make calculating their volume easier?

Yes, Jordan domains have the property of being convex, which means that any straight line connecting two points within the domain lies completely within the domain. This property makes it easier to calculate the volume of linear transformations of Jordan domains.

5. Can the volume of linear transformations of Jordan domains be negative?

No, the volume of linear transformations of Jordan domains is always positive. This is because the determinant of the transformation matrix, which is used in the calculation, is always positive. Therefore, the volume of the transformed domain is always a positive multiple of the original volume.

Similar threads

  • Calculus and Beyond Homework Help
Replies
3
Views
626
  • Calculus and Beyond Homework Help
Replies
7
Views
485
  • Calculus and Beyond Homework Help
Replies
2
Views
909
  • Calculus and Beyond Homework Help
Replies
11
Views
1K
  • Calculus and Beyond Homework Help
Replies
7
Views
2K
  • Calculus and Beyond Homework Help
Replies
1
Views
1K
  • Linear and Abstract Algebra
Replies
1
Views
2K
  • Calculus and Beyond Homework Help
Replies
9
Views
1K
  • Calculus and Beyond Homework Help
Replies
1
Views
1K
  • Calculus and Beyond Homework Help
Replies
3
Views
1K
Back
Top