Thermodynamics: Proofs of work done on/by gas during adiabatic process

In summary, the conversation discusses the derivation of the work done on a gas during a quasistatic adiabatic compression, as well as the work done by a gas during such a compression. The formula for the work done is given, as well as the attempt at a solution. There is confusion about the signs and the correct derivation, but it is eventually concluded that the formula is W = - \frac{P_f V_f - P_i V_i}{1 - \gamma}=\frac{P_f V_f - P_i V_i}{\gamma-1}=\frac{P_i V_i - P_f V_f}{1 - \gamma}. The individual discussing the problem expresses gratitude for the help provided.
  • #1
Matty R
83
0
Hello

I'm really confused with this and would appreciate any help.

Homework Statement



a) Show that the work done on a gas during a quasistatic adiabatic compression is given by:

[tex]W = \frac{P_f V_f - P_i V_i}{\gamma - 1}[/tex]

b) Show that the work done by a gas during a quasistatic adiabatic compression is given by:

[tex]w = \frac{P_i V_i - P_f V_f}{\gamma - 1}[/tex]


Homework Equations



[tex]w = -W[/tex]
[tex]PV^{\gamma} = K[/tex]


The Attempt at a Solution



a) [tex]dW = -PdV[/tex]
[tex]P = KV^{- \gamma}[/tex]
[tex]W = -K \left[\frac{V^{1- \gamma}}{1 - \gamma} \right]^{V_f} _{V_i}[/tex]
[tex]W = - \frac{P_f V_f - P_i V_i}{1 - \gamma}[/tex]
[tex]W = \frac{P_i V_i - P_f V_f}{\gamma - 1}[/tex]

I don't understand where I've gone wrong.

b) [tex]w = -W[/tex]
[tex]w = - \frac{P_i V_i - P_f V_f}{\gamma - 1}[/tex]
[tex]w = \frac{P_f V_f - P_i V_i}{1 - \gamma}[/tex]

I also get this answer if I derive w from:

[tex]dw = PdV[/tex]

I've probably got a minus sign mixed up, or something like that, but I've been through the derivation so many times it's invading my dreams. Okay, maybe it isn't that bad, but I'm really struggling.
 
Physics news on Phys.org
  • #2
Matty R said:
Hello

I'm really confused with this and would appreciate any help.

Homework Statement



a) Show that the work done on a gas during a quasistatic adiabatic compression is given by:

[tex]W = \frac{P_f V_f - P_i V_i}{\gamma - 1}[/tex]


[tex]w = -W[/tex]
[tex]PV^{\gamma} = K[/tex]


The Attempt at a Solution



a) [tex]dW = -PdV[/tex]
[tex]P = KV^{- \gamma}[/tex]
[tex]W = -K \left[\frac{V^{1- \gamma}}{1 - \gamma} \right]^{V_f} _{V_i}[/tex]
[tex]W = - \frac{P_f V_f - P_i V_i}{1 - \gamma}[/tex]
[tex]W = \frac{P_i V_i - P_f V_f}{\gamma - 1}[/tex]

I don't understand where I've gone wrong.


You have changed sign too many times:-p.
[tex]W = - \frac{P_f V_f - P_i V_i}{1 - \gamma}=\frac{P_f V_f - P_i V_i}{\gamma-1}[/tex]
 
  • #3
Thanks for the reply.

So, erm, is this true:

[tex]W = - \frac{P_f V_f - P_i V_i}{1 - \gamma}[/tex]
[tex]= \frac{P_f V_f - P_i V_i}{\gamma-1}[/tex]
[tex]= \frac{P_i V_i - P_f V_f}{1 - \gamma}[/tex]
 
  • #4
Matty R said:
So, erm, is this true:

[tex]W = - \frac{P_f V_f - P_i V_i}{1 - \gamma}[/tex]
[tex]= \frac{P_f V_f - P_i V_i}{\gamma-1}[/tex]
[tex]= \frac{P_i V_i - P_f V_f}{1 - \gamma}[/tex]

Yes.

ehild
 
  • #5
Thank you very much for your help.

I'm feeling quite embarrassed now, though most of the threads I've created here have been about really basic mistakes, so I should be used to it. :rolleyes:
 

Related to Thermodynamics: Proofs of work done on/by gas during adiabatic process

What is Thermodynamics?

Thermodynamics is a branch of physics that deals with the study of heat and its relationship to energy and work. It explains how energy is transferred between different forms and how it affects the behavior of matter.

What is an adiabatic process?

An adiabatic process is a thermodynamic process in which no heat is exchanged between a system and its surroundings. This means that the change in internal energy of the system is equal to the work done on or by the system.

How is work done on a gas during an adiabatic process?

Work is done on a gas during an adiabatic process when the gas is compressed or expanded against a piston or other external force. This results in a change in the volume and pressure of the gas, which in turn changes its internal energy.

What is the first law of thermodynamics?

The first law of thermodynamics states that energy cannot be created or destroyed, but it can be converted from one form to another. In the case of an adiabatic process, the first law states that the change in internal energy of the system is equal to the work done on or by the system.

How can we prove work done on a gas during an adiabatic process?

The work done on a gas during an adiabatic process can be proven using the ideal gas law and the equation for the change in internal energy. By substituting these equations and solving for work, we can determine the amount of work done on the gas during the adiabatic process.

Similar threads

  • Introductory Physics Homework Help
Replies
4
Views
722
  • Introductory Physics Homework Help
Replies
3
Views
1K
  • Introductory Physics Homework Help
Replies
1
Views
536
  • Introductory Physics Homework Help
Replies
4
Views
882
  • Introductory Physics Homework Help
Replies
1
Views
1K
  • Introductory Physics Homework Help
Replies
12
Views
827
  • Introductory Physics Homework Help
Replies
8
Views
5K
  • Introductory Physics Homework Help
Replies
3
Views
243
  • Introductory Physics Homework Help
Replies
4
Views
712
  • Introductory Physics Homework Help
Replies
19
Views
1K
Back
Top