Special relativity transformations

In summary, the question involves two light flashes occurring on the laboratory x axis, with one at time t=0 and position x=450 m, and the other at time t=+1 ms at the origin. In an inertial frame moving along the x-axis with an unknown speed v, the events are observed to be simultaneous. The relevant equations for this problem are the Lorentz transformations, but using the given numbers yields a non-physical result. It is possible that there is a misprint in the question, as confirmed by the lecturer.
  • #1
zhillyz
67
0

Homework Statement



Two light flashes occur on the laboratory x axis, the first at time t=0 and
position x=450 m, the second at time t=+1 ms, at the origin. In an inertial
frame moving along the x-axis with speed v, the events are simultaneous.
What is the speed v?

Homework Equations



From the question I have decided that the relevant equations are the Lorentz transformations. We know the position's in the rest frame and we know the time of the events. In the moving frame we know the the events are simultaneous. So we can't use the transforms for x as there would be two unknowns [itex]\Delta x'[/itex]and [itex]v[/itex]

The Attempt at a Solution



[itex] t_{1}' = \gamma (t_{1} - \dfrac{vx_{1}}{c^2})[/itex]
[itex] t_{2}' = \gamma (t_{2} - \dfrac{vx_{2}}{c^2})[/itex]

[itex] t_{2-1}' = \gamma (t_{2} -t_{1} - \dfrac{v}{c^2}(x_{2} - x_{1}))[/itex]

[itex] 0 = \gamma((1*10^-3) - 450\dfrac{v}{c^2})[/itex]

[itex] 0 =(1*10^-3) \gamma - \gamma 450\dfrac{v}{c^2}[/itex]

[itex] \gamma 450\dfrac{v}{c^2} =(1*10^-3) \gamma [/itex]

[itex] 450\dfrac{v}{c^2} = (1*10^-3) [/itex]

[itex] v = \dfrac{(1*10^-3)}{450} c^2 \mbox{WRONG!}[/itex]

Not sure what I am doing wrong. Any help on how to tackle these questions would be great.
 
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  • #2
Unless question sheet is a misprint and it should be micro rather than milli(seconds)?
 
  • #3
Your reasoning seems to be correct, and using the numbers given does give a non-physical result, so you are perhaps correct in thinking that there is a misprint in the question.
 
  • #4
Thanks, my lecturer got back to me and confirmed this :). I appreciate you taking the time.
 
  • #5


It seems like you are on the right track by using the Lorentz transformations, but there are a few mistakes in your calculation. First, you have used the wrong value for t1 in your first equation. It should be t1 = 0, since the first event occurs at t=0 in the rest frame. Second, you have used the wrong value for t2 in your second equation. It should be t2 = 1 ms, since the second event occurs at t = +1 ms in the rest frame. Third, you have used the wrong value for x2 in your last equation. It should be x2 = 0, since the second event occurs at the origin in the rest frame.

Also, keep in mind that the Lorentz transformations involve the speed of light, c, not c^2. So the correct equation should be 450v/c = 1*10^-3. Solving for v gives you v = 2.22*10^6 m/s.

Hope this helps! Remember to always double check your inputs and units when using equations in physics.
 

Related to Special relativity transformations

1. What is special relativity?

Special relativity is a theory developed by Albert Einstein in 1905 that explains the relationship between space and time. It states that the laws of physics are the same for all observers in uniform motion and that the speed of light is constant in all inertial frames of reference.

2. What is the difference between special relativity and general relativity?

Special relativity deals with the effects of motion on space and time, while general relativity incorporates the effects of gravity on these concepts. General relativity is a more comprehensive theory that supersedes special relativity.

3. What are the fundamental principles of special relativity?

The two main principles of special relativity are the principle of relativity, which states that the laws of physics are the same for all observers in uniform motion, and the principle of the constancy of the speed of light, which states that the speed of light is always the same regardless of the observer's frame of reference.

4. What are Lorentz transformations in special relativity?

Lorentz transformations are mathematical equations that describe how measurements of space and time change between two different inertial frames of reference. They are used to calculate the effects of relative motion on physical quantities, such as length and time intervals.

5. What are some real-world applications of special relativity?

Special relativity has several practical applications, including GPS technology, particle accelerators, and nuclear power plants. It also helps explain phenomena such as time dilation and length contraction in high-speed objects.

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