- #1
nobahar
- 497
- 2
Hello, this is a question from a pure mathematics textbook:
(2D vectors)
The vectors a and b are of equal magnitute k (k does not equal 0), and the angle between a and b is 60 degrees. If c=3a-b and d=2a-10b
A) Show that c and d are perpendicular vectors.
(Sadler, A.J., Thorning, D.W.S (2007, pg.63). Understanding Pure Mathematics, Glasgow: Oxford Universty Press).
c.d=0
=|c||d|cos(90)
Therefore, c.d/|c||d|=cos(90)
'Normally' for the dot product, the coefficients of the 'i' component of the two vectors are multiplied togeather, and the same process is applied to the j components, then they are added togeather.
I would attempt the question, but to be honest I'm not sure what steps to take; since my base vectors a and b are not orthogonal. Am I using the correct method? An answer would be much appreciated, I apologise for the language used and the presentation, I hope its accurate.
(2D vectors)
The vectors a and b are of equal magnitute k (k does not equal 0), and the angle between a and b is 60 degrees. If c=3a-b and d=2a-10b
A) Show that c and d are perpendicular vectors.
(Sadler, A.J., Thorning, D.W.S (2007, pg.63). Understanding Pure Mathematics, Glasgow: Oxford Universty Press).
c.d=0
=|c||d|cos(90)
Therefore, c.d/|c||d|=cos(90)
'Normally' for the dot product, the coefficients of the 'i' component of the two vectors are multiplied togeather, and the same process is applied to the j components, then they are added togeather.
I would attempt the question, but to be honest I'm not sure what steps to take; since my base vectors a and b are not orthogonal. Am I using the correct method? An answer would be much appreciated, I apologise for the language used and the presentation, I hope its accurate.