Noether current in quantum field theory

  • #1
CSpring432
1
0
Homework Statement
Finding Noether current for the given action
Relevant Equations
$$J^{\mu}=\frac{\partial L(\phi, \partial (\phi))}{\partial (\partial _{\mu}(\phi)}(\delta_{\alpha}\phi)-F^{\mu}$$
Hi

Have been trying to solve the below question for a while, wondered if anyone could help.

Considering the action

$$S=\int -\frac{1}{2}\sum^2_{n,m=1} (\partial^{\mu}\phi_{nm}\partial_{\mu}\phi_{mn}+m^2 \phi_{nm} \phi_{mn})dx$$
under the transformation

$$\phi'=e^{\alpha}\phi e^{-\alpha}$$

Find the infinitesimal transformation and associated Noether current, where both ##\alpha## and ##\phi## are real 2x2 matrices.

I've managed to find what (I think) is the infinitesimal transformation:

$$e^{\alpha}\phi e^{-\alpha}\approx \phi-\phi \alpha +\alpha\phi+ \mathcal{O}(\alpha^2)$$
$$\therefore \delta_{\alpha}=[\alpha, \phi]$$

I am however, stumped for calculating the Noether constant. I know that I would have to use the formula

$$J^{\mu}=\frac{\partial L(\phi, \partial (\phi))}{\partial (\partial _{\mu}(\phi)}(\delta_{\alpha}\phi)-F^{\mu}$$

The issue, I think, is calculating the covariant derivatives since the phi terms are matrix elements. Any help would be really appreciated.
 
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  • #2
I think that ##\phi## represents four real fields ##\phi_{nm}## and the first term in the Noether current is
$$\sum^2_{n,m=1}\frac{\partial L(\phi, \partial (\phi))}{\partial (\partial _{\mu}(\phi_{nm}))}(\delta_{\alpha}\phi_{nm})$$
 

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