- #1
YODA0311
- 26
- 0
probability help pleasezz
1. In how many ways can three aces be drawn?
2. I used this formula - P= n!/(n-r)!
n r
3. Here is my attempt- 52!/(52-3)!=52!/49!= 132600, but that is off to me.
I googled this problem and the person got "There are 4*3*2 = 24 sequences in which 3 aces can be drawn from a deck containing 4 aces." However I do not know how they reached their conclusion :(
1. In how many ways can three aces be drawn?
2. I used this formula - P= n!/(n-r)!
n r
3. Here is my attempt- 52!/(52-3)!=52!/49!= 132600, but that is off to me.
I googled this problem and the person got "There are 4*3*2 = 24 sequences in which 3 aces can be drawn from a deck containing 4 aces." However I do not know how they reached their conclusion :(