- #1
skg94
- 79
- 0
Homework Statement
What is the electric field at the third vertex.
http://tinypic.com/r/350toif/6
edit- not working actual link works = http://tinypic.com/r/350toif/6
Homework Equations
E=kq/r^2
The Attempt at a Solution
E1= (labeled on the diagram) = (8.99*10^9)(4)/(.02)^2 = 8.99*10^13
E2 = same, since equal triangle
E1x= 8.99*10^13cos60=7.78556838*10^13
E1y= " sin60 = 4.495*10^13
Now if my theory is right, this x and y are n of e so both are positive.
E2x= -7.78556838*10^13
E2y= 4.495*10^13
Ex= E1x+E2x=0
Ey=E1y+E2y=8.99*10^13
[itex]\sqrt{Ex^2+Ey^2}[/itex] = 8.99*10^13
which isn't the answer i don't know where I've gone wrong
answers on the picture, 1.56*10^14 N/c