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Charles123
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What exactly makes the motor consume the electrical energy? I s heat dissipation higher that in a normal coil? Is it counter-electromotive force? What makes the voltage drop?
Thank you
regards
Thank you
regards
Charles123 said:What exactly makes the motor consume the electrical energy? I s heat dissipation higher that in a normal coil? Is it counter-electromotive force? What makes the voltage drop?
Thank you
regards
Charles123 said:Thank you for your answer!
I understand how they work, how electrical energy produces mechanical energy. My question is how is the electrical energy consumed/dissipated?
Heat, but more than if the motor wasn`t there? If so, why?
For instance in an incandescent light bulb it's easy to see that it’s the structure of the filament itself that produces the resistance, and its due to that resistance that heat and the desired light is produced. In the electrical motor one uses the magnetic field generated by the current passing in the electromagnets to interact with the current passing in the wires wrapped around the armature making the armature move (generation of mechanical energy). But by what mechanisms does the voltage drop?
Regards"
Charles123 said:Thank you for your answer!
I understand how they work, how electrical energy produces mechanical energy. My question is how is the electrical energy consumed/dissipated?
Heat, but more than if the motor wasn`t there? If so, why?
For instance in an incandescent light bulb it's easy to see that it’s the structure of the filament itself that produces the resistance, and its due to that resistance that heat and the desired light is produced. In the electrical motor one uses the magnetic field generated by the current passing in the electromagnets to interact with the current passing in the wires wrapped around the armature making the armature move (generation of mechanical energy). But by what mechanisms does the voltage drop?
Regards"
Charles123 said:What exactly makes the motor consume the electrical energy? I s heat dissipation higher that in a normal coil? Is it counter-electromotive force? What makes the voltage drop?
Thank you
regards
Charles123 said:CWatters, thank you for your answer.
"In an ideal motor all the electrical energy is turned into mechanical energy and there are no losses.", I understand this conceptually, but how does it happen? How is the electrical energy transformed? What makes the voltage drop?
Regards
Lsos said:Charles123 the simple answer to your question, per my understanding, is indeed "back emf".
Electrons flow through the wire, creating a magnetic field which pushes the wire/ motor. If the motor turns as a result of this and there's any load on it, then that load will push back on the motor, which will push back on the magnetic field, which will push back on the electrons.
Charles123 said:pgardn:
"Because the motor is no longer a motor.
Its just essentially a long piece of wire. Long thin wire that attaches to the terminals of a battery so that current flows." - So the fact that it is now a resistor has only to do with the characteristics of the wires?
"Work IS still done because there is an electric field in the wire. The electric field does work on the electrons. They are forced over a distance of Efield within the wire." - you are of course right, I meant no mechanical work making the rotor turn.
Lsos, thank you for your answer! So back emf is the answer then…
truesearch said:What do you mean by 'back emf is the answer'.
Do you know how to calculate back emf?
what is your background knowledge, your profile gives no clues, what textbooks on this topiuc have you referred to?...were they of no help?
Charles123 said:CWatters, thank you for your answer.
"In an ideal motor all the electrical energy is turned into mechanical energy and there are no losses.", I understand this conceptually, but how does it happen? How is the electrical energy transformed? What makes the voltage drop?
Regards
Charles123 said:pgardn:
"I don't understand which fields are doing work and at what points in time in the motor/battery setup. And that is the essence of understanding the energy situations in your very first post that I did not realize, for me. Work. I personally get myself to understand most of this stuff with fields and a reference object and what is doing work on that object through a series of events. I cannot manage that with this problem. Maybe you understand what fields are doing work on electrons, or the electrons within the lattice, during the different phases of a motor turning?" - I am sorry, but I don’t follow.
"As for case I. I was already assuming the wires had the same resistance. Therefore there are two diff ranges of energy allowed for the electrons. 1. in the battery 2. In the wire. No motor necessary." - I don`t understand either. The motor has to have some effect, doesn't it? If we are holding the motor still, we are applying a force equal to the one applied in the rotor trough electromagnetism. Therefore mechanical work is not being done, so all energy has to be dissipated as heat. Am I wrong?
Lsos:
You just gave your input, an important one to the discussion, thank you for that!
In regards to your second post, see my second comment above…
CWatters:
"In an ideal motor with zero losses there is not voltage drop and it allways runs flat out regardless of the load." - If this was accurate then power going in the motor would equal power going out, so you would not be transforming electrical energy in mechanical energy, but creating mechanical energy maintaining all the electrical one. You could have as much motors in series as you wanted…
"Back to the real world motor...Consider what happens when you stall the motor. The only thing limiting the current is the coil and brush resistance. All the voltage drop appears across these." - again, If we are holding the motor still, we are applying a force equal to the one applied in the rotor trough electromagnetism. Therefore mechanical work is not being done, so all energy has to be dissipated as heat. There has to be an extra effect besides the normal resistance of the wires.
sophiecentaur:
" There is no essential difference between the electrical energy being transferred to thermal in the resistance and into 'bulk' kinetic as the motor moves. The thermal energy that turns up in the hot resistor is only another manifestation of kinetic energy - it's just randomised." -Agree.
Can you give some input to how we "loose" the electrical energy in the motor. Power in must be higher that power going out the motor, regardless of the fact that we let the rotor turn or not. By what mechanisn(s)?
Thank you all for your inputs!