Finding the Speed of Rain in Relative Motion

In summary, the rain appears to fall vertically when the man is walking and then when he doubles his speed it falls at a 30 degree angle.
  • #1
kalupahana
36
0
Relative motion prob, please help

Homework Statement


A man walk at a rate of 2 km/h; A rain appears to fall vertically. when he doubled his speed it appears to fall at 30o vertical. Find the real speed of the rain.


Homework Equations





The Attempt at a Solution


Help me to do this question. I cannot understand what my teacher said about relative motion. Please explain me how find the answer for this question.
 
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  • #2
hi kalupahana! :wink:

let VMG be the velocity of the Man relative to the Ground,
VRG be the velocity of the Rain relative to the Ground,
and VRM be the velocity of the Rain relative to the Man

then draw a vector triangle MRG for each of the two situations: the length of the RG side will be the same in both triangles, and the length of the MG side will be 2 in one triangle and 4 in the other triangle :smile:

(see the pf library entry on vector triangle for some more details)
 
  • #3


tiny-tim said:
hi kalupahana! :wink:

let VMG be the velocity of the Man relative to the Ground,
VRG be the velocity of the Rain relative to the Ground,
and VRM be the velocity of the Rain relative to the Man

then draw a vector triangle MRG for each of the two situations: the length of the RG side will be the same in both triangles, and the length of the MG side will be 2 in one triangle and 4 in the other triangle :smile:

(see the pf library entry on vector triangle for some more details)

In both instance VRM is constant.
then sin60 = 2/x

x = 4/√3 = 2.3 km/h

is this right
 
  • #4
kalupahana said:
In both instance VRM is constant.

No, VRG is constant (it's the same Rain, so its velocity relative to the Ground is the same).

Try again … draw the two triangles, with a shared side …

what does it look like? :smile:
 
  • #5


tiny-tim said:
No, VRG is constant (it's the same Rain, so its velocity relative to the Ground is the same).

Try again … draw the two triangles, with a shared side …

what does it look like? :smile:

I got triangle like this

then tan60 = VRG /4
4√3 = VRG
 

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  • #6
hi kalupahana! :smile:

(just got up :zzz: …)

That's the right idea, but you've misinterpreted the question.

Your diagram show the rain falling vertically, but it doesn't.

Also, your arrows are going the wrong way round each vector triangle …

they have to match up so that VRG = VRM + VMG

(or VRM = VRG + VGM = VRG - VMG).

Try again. :smile:
 

Related to Finding the Speed of Rain in Relative Motion

1. What is relative motion?

Relative motion is the movement of an object in relation to another object. It takes into account the perspective and velocity of both objects.

2. How do you calculate relative motion?

To calculate relative motion, you need to determine the velocity of each object and their respective directions. Then, you can use the relative velocity formula (Vr = Vb - Va) to find the relative motion between the two objects.

3. What is the difference between relative motion and absolute motion?

Relative motion takes into account the motion of one object relative to another object, while absolute motion refers to the motion of an object in relation to a fixed point, such as the ground or a reference frame.

4. How does relative motion affect everyday life?

Relative motion can affect everyday life in various ways, such as when driving a car and passing another car, or when feeling the wind while riding a bike. It also plays a crucial role in understanding the movement of celestial bodies in space.

5. What are some real-world examples of relative motion problems?

Some examples of relative motion problems include calculating the speed of a boat crossing a river with a current, determining the velocity of a train relative to a stationary observer, and finding the relative velocity of two cars on a collision course.

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