Tension & Circular Motion Question - Looking for speed

  • #1
dcmf
16
5
Homework Statement
A person sitting in a chair (combined mass 80 kg) is attached to a 6.0-m-long cable. The person moves in a horizontal circle. The cable angle θ is 62 degrees below the horizontal. What is the person's speed? Note: The radius of the circle is not 6.0 m.
Relevant Equations
a = v^2/r
I have attached a screenshot of my rough work. First of all, is my interpretation of the question correct? Please see the diagram in purple. To me, this makes sense because a=v^2/r is the only equation from my coursework that seems to relates radius (which you can find from the length of the cable) and speed.
1707605967159.png
 
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  • #2
Hello @dcmf,
:welcome:

dcmf said:
is my interpretation of the question correct?
I guess so. Apparently the person is not in a wheelchair going around slowly ?

What do you do with the minus sign ?
And when I do the calculation, I get a different answer.

##\ ##
 
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  • #3
Welcome, @dcmf !

All the steps seem to be correct, but the final numerical calculation is incorrect.
As Tx and Ty are directly proportional to the horizontal and vertical accelerations respectively, you could have used those values directly.

##tan~28=ac/g##
 
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  • #4
Hi all, thank you for your replies. When you both said you're getting a different number doing the same calculation, I realized my calculator has been in radians and not degrees this entire time 🤡

Thanks for your patience and help :')
 
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  • #5
dcmf said:
my calculator has been in radians and not degrees
Happens often (and to all of us :wink:). Reason the more to check things, e.g. ##\sin(28^\circ)\approx 0.5## -- so you learn to smell a rat if you get ##0.27##

##\ ##
 
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  • #6
Screen Shot 2024-02-10 at 7.11.41 PM.png

How did you handle the negative sign under the radical? You can't simply ignore it because it shouldn't be there. Think about this because you might will get into trouble if you replace ##g## with ##-9.80~\text{m/s}^2## indiscriminately.
 
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Related to Tension & Circular Motion Question - Looking for speed

1. How does tension affect circular motion?

Tension in a string or rope can provide the centripetal force necessary to keep an object moving in a circular path. The tension force acts as the inward force required to maintain the object's velocity and prevent it from moving in a straight line.

2. How can I calculate the speed of an object in circular motion using tension?

To calculate the speed of an object in circular motion using tension, you can use the equation: Tension = (mass * velocity^2) / radius. Rearranging this equation will allow you to solve for the velocity of the object.

3. What happens to the speed of an object in circular motion if the tension in the string is increased?

If the tension in the string is increased, the speed of the object in circular motion will also increase. This is because the increased tension provides a greater centripetal force, allowing the object to move faster while maintaining its circular path.

4. Can tension in a string ever be greater than the weight of an object in circular motion?

Yes, tension in a string can be greater than the weight of an object in circular motion. This is necessary to provide the centripetal force required to keep the object moving in a circular path, especially if the object is moving at a high speed or has a small radius of curvature.

5. How does the radius of curvature affect the speed of an object in circular motion with tension?

The radius of curvature directly affects the speed of an object in circular motion with tension. A smaller radius of curvature requires a greater centripetal force, which means the object must move faster to maintain its circular path. Conversely, a larger radius of curvature requires less speed to maintain the circular motion.

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