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azzarooni88
- 10
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What happened to your equation. You're starting with the determinant equalling 0. You lost one side of your equation.azzarooni88 said:Homework Statement
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Homework Equations
Cofactor expansion (along 1st column)
The Attempt at a Solution
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solving the determinant equal to 0Mark44 said:What happened to your equation. You're starting with the determinant equalling 0. You lost one side of your equation.
If you're solving an equation, you have to actually have an equation.azzarooni88 said:solving the determinant equal to 0
I think my working is logical. I start off with 0=... and just don't continue writing 0 on the LHS as I solve for the RHS. Ultimately I get 0=x2 - x(b+a) +abMark44 said:If you're solving an equation, you have to actually have an equation.
In your first line, you start off with "= ..." followed by a bunch of expressions. You seem to have lost one side of your equation.
azzarooni88 said:I think my working is logical. I start off with 0=... and just don't continue writing 0 on the LHS as I solve for the RHS. Ultimately I get 0=x2 - x(b+a) +ab
A cofactor expansion solution is a method used to find the determinant of a matrix. It involves breaking down the matrix into smaller submatrices and calculating the determinants of those submatrices.
A cofactor expansion solution is useful when you have a small matrix with entries that are easy to work with. It is also helpful when you need to find the determinant of a matrix with entries that are not easily factorable.
The process for using cofactor expansion involves selecting a row or column of the matrix to expand from, then multiplying each entry in that row or column by its corresponding minor (the determinant of the submatrix formed by removing that entry). These products are then alternately added and subtracted to find the determinant of the original matrix.
Yes, cofactor expansion can be used on any size matrix. However, as the matrix gets larger, the process can become more time-consuming and complex.
One limitation of using cofactor expansion is that it can only be used for square matrices. Additionally, as mentioned earlier, as the matrix gets larger, the process becomes more complex and time-consuming.