Average Power Output for 260000 kg Jet at 9200m Altitude

[spockjones20]

Homework Statement

620 seconds after starting its take-off, a 260000 kg jet reaches its cruising altitude of 9200 meters and flies with a speed of 235 m/s. Neglecting friction, what has been the average power output of the engines?

Homework Equations

ΔKE = Work
Power = Work/time

The Attempt at a Solution

Initial KE = 0
Final KE = .5*260000*235^2 = 7179250000
Power = 7179250000/620 = 11579435.48 Watts

Can someone see an issue with what I am trying to do here? I tried to type in this answer but apparently it is wrong.

 

[OmCheeto]

Homework Statement

620 seconds after starting its take-off, a 260000 kg jet reaches its cruising altitude of 9200 meters and flies with a speed of 235 m/s. Neglecting friction, what has been the average power output of the engines?

Homework Equations

ΔKE = Work
Power = Work/time

The Attempt at a Solution

Initial KE = 0
Final KE = .5*260000*235^2 = 7179250000
Power = 7179250000/620 = 11579435.48 Watts

Can someone see an issue with what I am trying to do here? I tried to type in this answer but apparently it is wrong.

I haven't checked your math, but I can see you left out the change in potential energy.

 

[spockjones20]

Ok. Would that go into the work equation?

 

[OmCheeto]

Ok. Would that go into the work equation?

I believe so.

Try this: ΔKE + ΔPE = Work

and see what happens.

 

[Nickie]

I would like to point out that the given information is insufficient to accurately calculate the average power output of the engines. In order to calculate power, we need to know the amount of work done by the engines, which is dependent on factors such as the thrust produced by the engines and the time taken to reach cruising altitude. Additionally, neglecting friction may not accurately represent the real-world scenario. Without more information, it is not possible to accurately determine the average power output of the engines.