At resonance, the phase angle in an AC circuit is?

[alexavier]

At resonnance, the phase angle in an a.c circuit is ?pls need an answer.

2. the magnetic force on a charged particle moving with velocity v is ?
3. The current through a resistor in a.c circuit is given as 2 sin wt. Determine the d.c equivalent of the current?
4. What is the angle of dip at magnetic equator?


PEOPLE PLEASE TRY THESE QUESTIONSSSSSSSS.IF YOU CAN[/QUOTE]

 

[Hootenanny]

At resonnance, the phase angle in an a.c circuit is ?pls need an answer.

2. the magnetic force on a charged particle moving with velocity v is ?
3. The current through a resistor in a.c circuit is given as 2 sin wt. Determine the d.c equivalent of the current?
4. What is the angle of dip at magnetic equator?


PEOPLE PLEASE TRY THESE QUESTIONSSSSSSSS.IF YOU CAN

Hi alexavier and welcome to PF,

These seem like homework questions to me. It is the policy of PF not to provide answers or complete solutions to homework questions, instead you will learn more from us helping you to work-out the solution yourself.

So, what have you attempted thus far?

 

[Moetasim]

1. At resonance, the phase angle in an AC circuit is 0 degrees. This means that the voltage and current are in phase, which results in maximum power transfer in the circuit.

2. The magnetic force on a charged particle moving with velocity v is given by the equation F = qvBsinθ, where q is the charge of the particle, v is its velocity, B is the magnetic field, and θ is the angle between the velocity and the magnetic field.

3. The d.c equivalent of the given a.c current would be 2A, as the average value of sin wt over one cycle is 2/pi.

4. The angle of dip at the magnetic equator is 0 degrees, as the magnetic field lines are parallel to the surface of the Earth at this location.