- #1
Vriska
- 138
- 2
Homework Statement
apparently your effective power is V_maxI_max * cos(x) where x is the phase angle. So I must consider only real power
Homework Equations
power = VI
current = I sin(wt)
The Attempt at a Solution
Let impedence be = e^ix . I'll write current as Ie^i(wt) consideronly the real part, so V = e^(ix) *e^(iwt), sooo power is P = VI e^(ix)*e^(2iwt). Sooooooo...now what? take the real part? I don't know and ignore that 2iwt? I'm not quite comfortable with this notation.
random question :
is a phasors axes supposed to be a V vs I plot, I think there's something wrong with by textbook