What is Spinors: Definition and 130 Discussions

In geometry and physics, spinors are elements of a complex vector space that can be associated with Euclidean space. Like geometric vectors and more general tensors, spinors transform linearly when the Euclidean space is subjected to a slight (infinitesimal) rotation. However, when a sequence of such small rotations is composed (integrated) to form an overall final rotation, the resulting spinor transformation depends on which sequence of small rotations was used. Unlike vectors and tensors, a spinor transforms to its negative when the space is continuously rotated through a complete turn from 0° to 360° (see picture). This property characterizes spinors: spinors can be viewed as the "square roots" of vectors (although this is inaccurate and may be misleading; they are better viewed as "square roots" of sections of vector bundles – in the case of the exterior algebra bundle of the cotangent bundle, they thus become "square roots" of differential forms).
It is also possible to associate a substantially similar notion of spinor to Minkowski space, in which case the Lorentz transformations of special relativity play the role of rotations. Spinors were introduced in geometry by Élie Cartan in 1913. In the 1920s physicists discovered that spinors are essential to describe the intrinsic angular momentum, or "spin", of the electron and other subatomic particles.Spinors are characterized by the specific way in which they behave under rotations. They change in different ways depending not just on the overall final rotation, but the details of how that rotation was achieved (by a continuous path in the rotation group). There are two topologically distinguishable classes (homotopy classes) of paths through rotations that result in the same overall rotation, as illustrated by the belt trick puzzle. These two inequivalent classes yield spinor transformations of opposite sign. The spin group is the group of all rotations keeping track of the class. It doubly covers the rotation group, since each rotation can be obtained in two inequivalent ways as the endpoint of a path. The space of spinors by definition is equipped with a (complex) linear representation of the spin group, meaning that elements of the spin group act as linear transformations on the space of spinors, in a way that genuinely depends on the homotopy class. In mathematical terms, spinors are described by a double-valued projective representation of the rotation group SO(3).
Although spinors can be defined purely as elements of a representation space of the spin group (or its Lie algebra of infinitesimal rotations), they are typically defined as elements of a vector space that carries a linear representation of the Clifford algebra. The Clifford algebra is an associative algebra that can be constructed from Euclidean space and its inner product in a basis-independent way. Both the spin group and its Lie algebra are embedded inside the Clifford algebra in a natural way, and in applications the Clifford algebra is often the easiest to work with. A Clifford space operates on a spinor space, and the elements of a spinor space are spinors. After choosing an orthonormal basis of Euclidean space, a representation of the Clifford algebra is generated by gamma matrices, matrices that satisfy a set of canonical anti-commutation relations. The spinors are the column vectors on which these matrices act. In three Euclidean dimensions, for instance, the Pauli spin matrices are a set of gamma matrices, and the two-component complex column vectors on which these matrices act are spinors. However, the particular matrix representation of the Clifford algebra, hence what precisely constitutes a "column vector" (or spinor), involves the choice of basis and gamma matrices in an essential way. As a representation of the spin group, this realization of spinors as (complex) column vectors will either be irreducible if the dimension is odd, or it will decompose into a pair of so-called "half-spin" or Weyl representations if the dimension is even.

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  1. U

    Question about spinors and gamma-matrices

    I'm working on a realisation of an exceptional group. I'm having some troubles with spinors. Here goes: Given a Weyl-spinor of so(6,6) (let's say the chiral one). Under the decomposition of so(6,6) into so(5,5) + u(1), what does the spinor split into? Two different Weyl-spinors (of so(5,5))...
  2. Spinnor

    Exploring Real Fields and Spinors: Understanding Movement in Tangent Space

    Suppose we have a real field, S(x,y,z,t), that satisfies E^2 = P^2 + m^2. Here the tangent space could be R^1? Say we can expand the tangent space and let it be R^3 but make the restriction that "movement" of the field in the tangent space was restricted to some orbit about the origin of the...
  3. I

    What is the construction of gamma matrices and spinors in higher dimensions?

    Dear guys, I want to understand the spinors in various dimensions and Clifford algebra. I tried to read the appendix B of Polchinski's volume II of his string theory book. But it's hard for me to follow and I stuck in the very beginning. I will try to figure out the outline and post my...
  4. P

    Peskin Schroeder Problem 5.6 (b) Weyl spinors

    Hey! I have a problem with problem 5.6 (b) from Peskin + Schroeder. Maybe I just don't see how it works, but I hope somebody can help me! Homework Statement We are asked to calculate the amplitude for the annihilation of a positron electron pair into two photons in the high-energy limit. The...
  5. D

    Consider parity then it is no longer enough to talk about two spinors

    Ryder in chapter two of his book says that if we consider parity then it is no longer enough to talk about two spinors and so he introduces 4 spinors. Is there some postulate of Quantum physics that has to do with state trasformation under parity??
  6. Spinnor

    From Cartan's Theory of Spinors, x1^2 + x2^2 + x3^2 = 0

    Let x1, x2, x3 be the components of a complex vector. If x1^2 + x2^2 + x3^2 = 0 Cartan calls this a isotropic vector. So if, x1 = a*exp(i*theta) then x1^2 = a^2*exp(2*i*theta) ? I think I'm being confused with what I read here, http://www.sjsu.edu/faculty/watkins/spinor.htm in...
  7. Spinnor

    3D phase space of point particle and spinors.

    Can we make a connection? Consider the phase space of a point particle in R^3. Six numbers are required, three for position and three for velocity. Now consider an isotropic vector, X, in C^3 with X*X = 0. X = (x1,x2,x3), X*X = (x1*x1 + x2*x2 + x3*x3), x1 = c1 + i*c2, x1*x1 = (c1*c1 +...
  8. N

    Do Weyl Spinors Have Well-Defined Helicities Across Different Masses?

    Weyl spinors are not eigenstates of the helicity operator when the mass is not zero. But they have well-defined chiralities no matter what the mass is. Yet, it seems to me that references keep talking of Weyl spinors as if they have well-defined helicities, regardless of the mass...
  9. Hepth

    Scattering matrix to traces/dirac spinors

    I've been searching online and in my qft books (im an early phd student) and I can't find a clear explanation. If you have one, or can simply direct me to a page that does please do so. For a generic scattering/decay matrix : \sum _{polarization} \left|M|^2\right.=\sum _{polarization}...
  10. N

    Spinors and spatial coordinates

    I was reading a web page (http://electron6.phys.utk.edu/qm1/modules/m12/spinor.htm) that claims that the state vector of a spin-1/2 particle is completely specified by a two-component spinor, just as the state vector of a spinless particle is completely specified by its components in position...
  11. S

    Explaining Conformal Killing Spinors

    This could have gone in about 4 different forums, so I apologize if I picked the wrong one. I'm wondering if anyone can explain what (conformal) killing spinors are all about. All I can find is that they are sections of the spinor bundle of a spin manifold satisfying: \nabla_\mu \epsilon =...
  12. H

    Martin Kober: The relation of a unified QFT of spinors to the structure of GR

    As suggested by Marcus, I have read the whole paper and decided to start a discussion of Kober's paper by asking a few questions. The paper certaintly presents a very interesting view. Part of it is an extension of Heisenberg's work on unified QFT, that the mass originates from self-interaction...
  13. B

    Dirac Spinors Suck: QFT Calculations with Weyl Spinors

    I think that anyone who has done a course in QFT has had their progress hampered by AT LEAST a month by Dirac Spinors. Why is it that the only sensible way to write the Standard Model down is to use Weyl Spinors, but the only sensible way to do calculations is to use Dirac spinors and...
  14. Z

    A simple question on the algebra of pure spinors in 10 dimensions

    Hi. I'm looking at Berkovits' pure spinor formulism of string theory. I am a PhD student studying mathematics and so am having trouble with some of the physics behind the mathematics. Say we have V a 10 dimensional vector space and we pick an irreducible representation of Spin(V) - which is...
  15. B

    Action of Clifford-elements on vectors & spinors

    Hi all! I am currently preparing a talk about Clifford algebras and pin/spin-groups. Since half the audience will consist of physicians (as I am myself) I also want to get more into the connection of the mathematical definitions and derivations (as one may find in Baker, "Matrix groups" or...
  16. N

    Spinors in d dimensions and Clifford algebra

    I bought a book on susy and there is a chapter on spinors in d-dimensions. Now, maybe I am extremely dumb but I just can't understand the first few lines! EDIT: I was being very dumb except that I think there is a typo...See below... BEGINNING OF QUOTE Consider a d-dimensional...
  17. J

    Why there are no spinors for GL(n)

    Does anybody know a simple proof of the fact that there are no finite-dimensional extensions of the \textsl{so(n)}-spinor representation to the group of general linear transformations. The proof seems can be based on the well-known fact that when rotated 2\pi a spinor transforms...
  18. M

    Why Do GUT Theories Only Use Left Spinors?

    Why in every single text about GUT theories only the left spinors are used? Why use the conjugate of the spinor instead of the spinor itself? Is it just a another historic definition? Thanks
  19. K

    Is there a relation between GCT and Lorentz invariance?

    I am not sure where to post this question since it involves GR and particle physics but here it goes. I am reading in a book that when coupling a spinor to gravity, one replaces \partial_\mu \psi [/tex] by a covariant derivative D_\mu \psi [/tex] which must transform like a spinor under...
  20. A

    Commuting metric past Dirac spinors?

    I'm wondering how in Peskin & Schroeder they go from i\mathcal{M} = {\overline{v}^s^'} (p^{'}) (-ie\gamma^\mu)u^s(p) \left( \frac{-ig_{\mu\nu}}{q^2} \right) \overline{u}^r (k) (-ie\gamma^\nu) v^{r^{'}} (k) at the bottom of page 131 to (5.1) at the top of 132 which reads i\mathcal{M}...
  21. C

    Are spinors just wavefunctions in the dirac field?

    are spinors just wavefunctions in the dirac field?
  22. pellis

    Fermions with mass, and null spinors

    Are spinor wave functions describing e.g. electrons, necessarily describing them as massless? Spinors representing physical entities are often described as corresponding to null vectors in space-time, which suggests that they can only describe massless entities. Nevertheless, the Dirac...
  23. M

    Spinor Boosts: Weinberg's QFT Book Insights on Rotation and Momentum Effects

    Weinberg shows in his book on QFT that the effect of a rotation on a massive particle's spin is the same as applying exp(-i \theta J.n) on the state, regardless of particle's momentum. In other words just rotate the spinor in its own representation. This makes calculations very simple. But what...
  24. B

    Lorentz Transformations and Spinors

    Hi, I have a question about spinors If \Lambda is a Lorentz Transformation what is (and how do you show that it is) the spinor representation of the Lorentz group ? I think it has somnething to do with the equivalence transformation S\dagger{\gamma}S=\Lambda\gamma But that is just a...
  25. K

    Eigenblades and the Geometric Algebra of Spinors

    I've been looking into Geometric Algebra approaches to linear transformations and have found it to be MUCH nicer than the conventional matrix approaches for certain kinds of transformations. Moreover, I find it much more intuitive, particularly in its way of dealing with complex numbers. For...
  26. arivero

    Separate normalisation of chiral spinors?

    When solving Dirac equation (for free massive particles) we usually impose normalisation conditions upon the eigenfunction in a single stroke. I am wondering, Is it possible/useful to impose separate normalisation conditions upon the left and right spinors? Should we still have a resolution...
  27. M

    General Relativity and Theory of Spinors

    Be kind with me I am just a dentist; nevertheless I am trying to understand the GR and the Theory of Spinors. In this sense I tried to explore the fundations of the GR and made use of a Taylorisation of the variations of the basis vectors de (with subscript 0, 1, 2 or 3) until the second order...
  28. D

    Proving Spin-1/2 Spinors are Eigenvectors to $\hat S^2$

    Can anyone give me some hints? I need to prove that all spinors to a spin-1/2 particle are eigenvectors to \hat S^2! /Daniel
  29. J

    Understanding Spinors: Not Your Typical Tensor

    What mathematically speaking is a spinor? Why isn't it a tensor? I didn't find the mathworld defintion very useful at all as it describes it as a complex column vector which really tells me nothing especially as we usually think of such an object as a tensor!
  30. T

    Pronouncing Spinors: A Self-Adjoint QM & GR Example

    Self Adjoint very nicely gave me an example when QM doesn't work with GR using something called Spinors which define quantum mechanical particles. i was wondering how exactly is spinors pronounced Is it like spinners umm like the rims lol :) ? Sorry for the odd question, I just don't...
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