I'm one of the few physics majors who never took physics or calculus in high school, and am currently a senior with a 3.9 GPa. Just be ready to work hard and you should be fine. High school preparation becomes increasingly irrelevant as you progress through college.
Since you want to know f(x) without all that "stuff" inside the parentheses, let u= 3x5. Then f(3x5)= f(u) and df/dx= (df/du)(du/dx)= (df/du)(15x)= 8x2. Now you have df/du= (8/15)x. Since u= 3x5, x5= u/3 and x= (u/3)1/5. df/du= (8/15)(u1/5)/31/5. Now just replace u by x to get f'(x)
I see...
Here's the problem:
d/dx(f(3x^5)) = 8x^2
Find f'(x)
After applying the chain rule:
f'(3x^5)(15x^4) = 8x^2
f'(3x^5) = 8/(15x^2)
It's not apparent to me how I proceed from here to find f'(x). I tried dividing the expression on the right by three and taking the fifth root but that does not...