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All its zeros are on the unit circle, aren't they?Why doesn't $1+z^{2^n}$ have zeros on the unit disc?
I don't think so. If we solve for z, we have $z = (-1)^{1/2^n}$All its zeros are on the unit circle, aren't they?
CB
\(z^{2n}=-1=e^{(2k+1)\pi i}, k \in \mathbb{Z}\)I don't think so. If we solve for z, we have $z = (-1)^{1/2^n}$