- #1
PFuser1232
- 479
- 20
In one dimension, the acceleration of a particle can be expressed as:
$$a = \frac{dv}{dt} = \frac{dx}{dt} \frac{dv}{dx} = v \frac{dv}{dx}$$
Does this equation imply that if ##v = 0## then ##a = 0##?
EDIT: I think I figured out the source of my confusion. This equation is a differential equation and I cannot just plug in values for ##v##, am I right?
$$a = \frac{dv}{dt} = \frac{dx}{dt} \frac{dv}{dx} = v \frac{dv}{dx}$$
Does this equation imply that if ##v = 0## then ##a = 0##?
EDIT: I think I figured out the source of my confusion. This equation is a differential equation and I cannot just plug in values for ##v##, am I right?
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