- #1
maNoFchangE
- 116
- 4
Suppose ##T## is an operator in a finite dimensional complex vector space and it has a zero eigenvalue. If ##v## is the corresponding eigenvector, then
$$
Tv=0v=0
$$
Does it mean then that ##\textrm{null }T## consists of all eigenvectors with the zero eigenvalue?
What if ##T## does not have zero eigenvalue? Does it mean that its null space is just the zero vector?
Thanks
$$
Tv=0v=0
$$
Does it mean then that ##\textrm{null }T## consists of all eigenvectors with the zero eigenvalue?
What if ##T## does not have zero eigenvalue? Does it mean that its null space is just the zero vector?
Thanks