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#### Lorena_Santoro

##### New member

- Dec 29, 2021

- 15

- Thread starter Lorena_Santoro
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- Thread starter
- #1

- Dec 29, 2021

- 15

- Mar 1, 2012

- 1,043

use the substitution $u = \sin(2x) \implies du = 2\cos(2x) \, dx$

$\displaystyle \dfrac{1}{2} \int_0^1 1-u^2 \, du$

you can finish up from here

- Thread starter
- #3

- Dec 29, 2021

- 15

Thank you!

use the substitution $u = \sin(2x) \implies du = 2\cos(2x) \, dx$

$\displaystyle \dfrac{1}{2} \int_0^1 1-u^2 \, du$

you can finish up from here