Work Done on an object by 3 Forces (Very Confused)

In summary, the diagram shows an overhead view of an object sliding on a floor. The x-y plane is the floor and the canister is free to slide in both the x and y directions.
  • #1
Travis Enigma
13
4
Homework Statement
The figure shows an overhead view of three horizontal forces acting on a cargo canister that was initially stationary but now moves across a frictionless floor. The force magnitudes are F1 = 3.00 N, F2 = 4.00 N, and F3 = 10.0 N, and the indicated angles are θ2 = 50.0˚ and θ3 = 35.0˚. What is the net work done on the canister by the three forces during the first 4.00 m of displacement?
Relevant Equations
W= F*d*cos(theta)
Here's a diagram of the object
IMG_3156.JPG
My Question: My friend and I were solving this problem. We both found Fxnet and Fynet. However to find work I did W= Fnet*d whereas he did W= Fxnet* d. He claims that since it's sliding on the floor it can only go in the x-direction, and it can't go in the y-direction. Which one of us is right?

My 2nd Question: I always thought the following x-axis: left and right, y-axis: forward and backward, z-axis: up and down. Is this right? If so, then how come my friend is telling me it's impossible for it to go in the y-axis because it can't go up since it sliding on a horizontal plane?
 
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  • #2
Maybe your friend doesn't realize that the figure shows an "overhead" view. So, the x-y plane is the floor. The canister is free to slide in both the x and y directions.
 
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  • #3
Travis Enigma said:
My 2nd Question: I always thought the following x-axis: left and right, y-axis: forward and backward, z-axis: up and down. Is this right? If so, then how come my friend is telling me it's impossible for it to go in the y-axis because it can't go up since it sliding on a horizontal plane?
There are no specific rules concerning the directions of the x, y, and z axes. If the axes are not specified in a problem, then you are free to choose the orientation of the axes as you wish. If the axes are given, as in this problem, then you need to make sure you see how the axes are oriented in 3D space. The 3 forces are given to be horizontal. So, the x-y plane is horizontal; i.e., parallel to the floor.
 
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  • #4
Travis Enigma said:
Homework Statement:: The figure shows an overhead view...

My Question: My friend and I were solving this problem. We both found Fxnet and Fynet. However to find work I did W= Fnet*d whereas he did W= Fxnet* d. He claims that since it's sliding on the floor it can only go in the x-direction, and it can't go in the y-direction. Which one of us is right?
The first sentence of the problem statement says "The figure shows an overhead view".
My 2nd Question: I always thought the following x-axis: left and right, y-axis: forward and backward, z-axis: up and down. Is this right?
It is purely a matter of convention. If you are working in two dimensions with one of them vertical (for instance, a child carrying a sled up a hill) then one would normally use x for horizontal and y for vertical.

If one is working in two dimensions with both of them horizontal (for instance, a race car on a circular course), one might well use x for east-west and y for north-south.

If one is using three dimensions, you are correct that the usual convention is x for east-west, y for north-south and z for up-down.

That said, unless the problem has already stated them, you are free to define axis directions and coordinate variable names as you please. Just clearly state your choices so that the teacher can understand what you are doing.

More generally...

Often, a good choice of coordinate system can simplify a problem significantly. Changing variable names can be a way to keep track of which coordinate system you are using.
 
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  • #5
Thank you both so much for your help, I understand now!
 

Related to Work Done on an object by 3 Forces (Very Confused)

1. What is work done on an object?

Work done on an object is the amount of energy transferred to or from the object by a force, resulting in a change in the object's velocity.

2. How is work calculated?

Work is calculated by multiplying the magnitude of the force applied to an object by the distance the object moves in the direction of the force.

3. What are the units of work?

The units of work are joules (J) in the SI system. In other systems, it can also be expressed in foot-pounds (ft-lb) or ergs (erg).

4. How is work done on an object by multiple forces calculated?

When multiple forces are acting on an object, the work done by each force is calculated separately and then added together to find the total work done on the object.

5. What is the net work done on an object?

The net work done on an object is the total work done by all the forces acting on the object. It can be positive, negative, or zero, depending on the direction and magnitude of the forces.

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