- #1
Jessica Sweet
- 10
- 0
Homework Statement
A person pulls a box (m=10 kg) horizontally with +2m/s2 acceleration by applying 45 N force. The displacement of the box is 8 meters from initial position.
a) How much work is done by applied force?
b) How much work is done by kinetic frictional force?
Homework Equations
Wf = Fcosθs
F=ma
Wfk = -Fks ?
Fk = μN ?
The Attempt at a Solution
I solved for part a, which was 360J.
I don't know how to solve for part b, which it seems like I would need the friction coefficient?
I tried Wfk = -(10)(2)(8) = -160 J, but that is incorrect.
How do I find Fk to solve for the work done by friction?
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