Work done by Hooke's Law? (Calc 2)

In summary, the conversation discussed an open tank in the shape of a right circular cone, measuring 8 feet across the top and 6 feet high. The question was how much work is done in emptying the tank by pumping the water over the top edge, given the weight-density of water as 62.4 pounds per cubic foot. The forum rules require relevant equations to be posted and an attempt at a solution to be shown in the appropriate homework forum. The thread has been closed.
  • #1
aimee2016
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0
An open tank has the shape of a right circular cone. The tank is 8 feet across the top and 6 feet high. How much work is done in emptying the tank by pumping the water over the top edge? (The weight-density of water is 62.4 pounds per cubic foot.)
 
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  • #2
aimee2016 said:
An open tank has the shape of a right circular cone. The tank is 8 feet across the top and 6 feet high. How much work is done in emptying the tank by pumping the water over the top edge? (The weight-density of water is 62.4 pounds per cubic foot.)
As per forum rules, you should post any standard equations you deem possibly relevant, and you must show some attempt.
 
  • #3
Please post in the appropriate homework forum, with the template filled out, including an attempt at a solution.

Thread closed.
 

Related to Work done by Hooke's Law? (Calc 2)

1. What is Hooke's Law?

Hooke's Law is a principle in physics that states the force required to extend or compress a spring is directly proportional to the distance the spring is stretched or compressed.

2. How is Hooke's Law used to calculate work done?

In order to calculate work done by Hooke's Law, you need to know the force applied to the spring and the distance it is stretched or compressed. The work done can be calculated by multiplying the force by the displacement.

3. What is the formula for calculating work done by Hooke's Law?

The formula for calculating work done by Hooke's Law is W = 1/2 * k * x^2, where W is the work done, k is the spring constant, and x is the distance the spring is stretched or compressed.

4. How does the spring constant affect the work done by Hooke's Law?

The spring constant directly affects the work done by Hooke's Law. A higher spring constant means the spring is stiffer, and therefore more force is required to stretch or compress it. This results in more work being done.

5. Can Hooke's Law be applied to other systems besides springs?

Yes, Hooke's Law can be applied to other systems besides springs as long as they exhibit linear elasticity. This means that the force required to deform the object is directly proportional to the amount of deformation.

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