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Lolagoeslala
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Homework Statement
A 2.75-kg potted plant rests on the floor. Determine the work required to move the
plant at a constant speed along the shelf for 1.07 m where the coefficient of kinetic friction is 0.549
The Attempt at a Solution
I found the Fn:
Fn = mg
Fn = 26.95 N
Ff = Fnμ
Ff = (26.95N)(0.549)
Ff = 14.79555 N
W = Ff x d
W = 14.79555 N x 1.07 m
W = - 15.8312 J
This would be negative correct?