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karush
Well-known member
- Jan 31, 2012
- 2,811
Find a formula for the sum of $n$ terms
Use the formula to find the limit as $n\to\infty$
$\displaystyle \lim_{n\to\infty}
\sum\limits_{i = 1}^{n}\frac{1}{n^3}(i-1)^2=
\displaystyle \lim_{x\to\infty}\frac{1}{n^3}
\sum\limits_{n = 1}^{n-1}i^2$
This was from an solution to the problem but i didn't understand the $n-1$ on top of the $\Sigma$ or how they got the $i^2$ from the given. there are more steps but ?? about this one
thnx ahead
my try at LateX today lots of previewing
Use the formula to find the limit as $n\to\infty$
$\displaystyle \lim_{n\to\infty}
\sum\limits_{i = 1}^{n}\frac{1}{n^3}(i-1)^2=
\displaystyle \lim_{x\to\infty}\frac{1}{n^3}
\sum\limits_{n = 1}^{n-1}i^2$
This was from an solution to the problem but i didn't understand the $n-1$ on top of the $\Sigma$ or how they got the $i^2$ from the given. there are more steps but ?? about this one
thnx ahead
my try at LateX today lots of previewing
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