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#### karush

##### Well-known member

- Jan 31, 2012

- 3,062

Find a formula for the sum of

Use the formula to find the limit as $n\to\infty$

$\displaystyle \lim_{n\to\infty}

\sum\limits_{i = 1}^{n}\frac{1}{n^3}(i-1)^2=

\displaystyle \lim_{x\to\infty}\frac{1}{n^3}

\sum\limits_{n = 1}^{n-1}i^2$

This was from an solution to the problem but i didn't understand the $n-1$ on top of the $\Sigma$ or how they got the $i^2$ from the given. there are more steps but ?? about this one

thnx ahead

my try at LateX today lots of previewing

**$n$**termsUse the formula to find the limit as $n\to\infty$

$\displaystyle \lim_{n\to\infty}

\sum\limits_{i = 1}^{n}\frac{1}{n^3}(i-1)^2=

\displaystyle \lim_{x\to\infty}\frac{1}{n^3}

\sum\limits_{n = 1}^{n-1}i^2$

This was from an solution to the problem but i didn't understand the $n-1$ on top of the $\Sigma$ or how they got the $i^2$ from the given. there are more steps but ?? about this one

thnx ahead

my try at LateX today lots of previewing

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