- #1
AznBoi
- 471
- 0
I'm confused by why my work is wrong:
[tex]3x^{2}+12x>0[/tex]
[tex]3x(x+4)>0[/tex]
3x>0 , x+4>0
x>0 , x>-4
However, the correct answers are: x>0 and x<-4? Why is the sign reversed on -4? I thought you were only suppose to reverse it if you multiply or divide the equation by a negative number?
[tex]3x^{2}+12x>0[/tex]
[tex]3x(x+4)>0[/tex]
3x>0 , x+4>0
x>0 , x>-4
However, the correct answers are: x>0 and x<-4? Why is the sign reversed on -4? I thought you were only suppose to reverse it if you multiply or divide the equation by a negative number?