Why don't fluorescent bulbs blow up when electricity is connected?

  • Thread starter supak111
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In summary: The ballast limits the current going through the bulb, and this, in turn, limits the amount of heat that can be generated.
  • #1
supak111
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Why don't fluorescent bulbs blow up when electricity is connected? My understanding is that gas inside heats up to plasma to make light. Wouldn't the heat of plasma expand the gas, add extra pressure and the pressure would break the glass? Maybe super low pressure inside the bulb to start with?
 
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  • #2
I'm a noob myself, so I'm not sure about your question. However, I got this off Wikipedia:

"A fluorescent lamp tube is filled with a gas containing low pressure mercury vapor and argon, xenon, neon, or krypton. The pressure inside the lamp is around 0.3% of atmospheric pressure." http://en.wikipedia.org/wiki/Fluorescent_lamp
 
  • #3
Yea I found that after my post too. .3% is really nothing, this means most fluorescent bulbs are basically empty vacuum with tiny tiny bit of gas.

Aaaand they all use ballasts, which basically controls how much electricity goes through the bulb. So I'm guessing here since the electricity is limited so is the temp/pressure inside the bulb. In other words, ballast is controlling pressure inside the bulb indirectly. Which keeps the pressure from exceeding the pressure at which the bulb glass would blow up.

Learn something new everyday
 
  • #4
supak111 said:
Yea I found that after my post too. .3% is really nothing, this means most fluorescent bulbs are basically empty vacuum with tiny tiny bit of gas.

Aaaand they all use ballasts, which basically controls how much electricity goes through the bulb. So I'm guessing here since the electricity is limited so is the temp/pressure inside the bulb. In other words, ballast is controlling pressure inside the bulb indirectly. Which keeps the pressure from exceeding the pressure at which the bulb glass would blow up.

Learn something new everyday

Without a ballast, the fuse would blow or the glass envelope would melt before the gas pressure became 'explosive'. Try working out the temperature you need to raise gas that starts at 0.3% AP before it would reach, say 2AP. (Assume the gas laws apply)
 
  • #5
Not everything "blows up" when you add pressure. The neon light bulb is strong enough to withstand the slight increase in air pressure inside it.
 
  • #6
Yes but tuning something into plasma isn't a slight increase in temp, its huge so the pressure would be huge too. But the use of a ballast to limit current and use of super low pressure in tubes explains why no booom!
 
  • #7
supak111 said:
Yes but tuning something into plasma isn't a slight increase in temp, its huge so the pressure would be huge too. But the use of a ballast to limit current and use of super low pressure in tubes explains why no booom!

I don't think the limit would be due to temperature-related pressure. It would be blown fuses long before that happened. You'd be limited, briefly, to an arc power of around 1.5kW in any domestic lighting circuit. That's not many Joules in the short time a fuse takes to operate.

But, of course, as you say, that's what the ballast is there for.
 
  • #8
supak111 said:
Why don't fluorescent bulbs blow up when electricity is connected? My understanding is that gas inside heats up to plasma to make light.

This is too much of a simplification. The emission isn't due to the temperature of the gas, it's due to the transfer of energy from the current in the ionised gas (which does not have to be particularly hot) to the electronic orbitals of the mercury vapour and the fluorescent material. These electrons then fall back to lower energy orbitals and emit in the visible light.
 
  • #9
MikeyW said:
This is too much of a simplification. The emission isn't due to the temperature of the gas, it's due to the transfer of energy from the current in the ionised gas (which does not have to be particularly hot) to the electronic orbitals of the mercury vapour and the fluorescent material. These electrons then fall back to lower energy orbitals and emit in the visible light.

Modern fluorescent lights produce UV which excites phosphors on the tube surface to produce broad band white(ish) light.

I have a feeling that there would be a limit to the current capacity of the column of gas - due to the number of available charge carriers - and hence the possible maximun power dissipation. I will try a back of a fag packet calculation to establish a ball park figure. Unless someone can do it first.
 
  • #10
I think sophiecentaur is right you have a given amount of mercury vapor which by the way is the current carrier in a gas discharge lamp not the gas itself because the voltages in a typical gas discharge lamp are not so high for them to make an arc that long over a gas like xenon and others.
So after the mercury vapor "burns out" the lamp can't start anymore or is failing after several seconds of operation.
Also using one without the ballast will in most cases result in a current overload which will burn out the mercury vapor and make the lamp useless again.
But even in these situations no explosion occurs a gas discharge lamp is not a grenade guys :)
 
  • #11
Is it OK to say 'fag packet' these days?
 
  • #12
sophiecentaur said:
Modern fluorescent lights produce UV which excites phosphors on the tube surface to produce broad band white(ish) light.

I don't think anything I said contradicts this.

Strictly speaking though, mercury has emission bands in the visible range.
 
  • #13
MikeyW said:
I don't think anything I said contradicts this.

Strictly speaking though, mercury has emission bands in the visible range.
I don't think I was contradicting you, either.
It is true that mercury vapour produces visible emissions. However, the light that is produced 'directly' is pretty unpleasant as a light source and plain old mercury lamps would only be used for high efficiency industrial lighting (and, I believe, the UV lamps that used to be available in Boot's the Chemist). It is the UV component that makes them suitable for domestic lighting because of the phosphors that are included these days. Iirc, the high power mercury lamps are of a fairly different construction to the domestic type - more along the lines of a mercury arc rectifier than a simple medium voltage fluo tube.
 
  • #14
BTW, Did a 'cigarette' packet calculation and I reckon that, even with the ions moving at c, with the density of (singly ionised) ions available, over a cross section of 1cm^2, you would limit at about 1800A. If you take into account the mean free path at that pressure and the application of only 200V total, I reckon the limiting current would be not many tens of amps because of the limited speed that the electrons can achieve in such a congested place.
That calculation was pretty rough and ready and I could be way out, of course. I may re-visit it when the mood takes me - or someone else could show just how wrong I could be. (Challenge)
I agree about the non-grenadelike nature of the process though!
 
  • #15
calculations are good ofcourse but this is one of those question to which you know the answer when you have atleast a basic understanding in physics and electricity.
 
  • #16
Crazymechanic said:
calculations are good ofcourse but this is one of those question to which you know the answer when you have atleast a basic understanding in physics and electricity.

umm. Not sure about that. The numbers really count in cases like this one, I think. The actual value of supply volts is highly relevant, for instance.
 

Related to Why don't fluorescent bulbs blow up when electricity is connected?

1. Why do fluorescent bulbs not blow up when electricity is connected?

Fluorescent bulbs are designed specifically to withstand the high levels of electricity needed to produce light. They are made with a gas-filled tube that is coated with a phosphor material. When electricity is applied, the gas inside the tube is excited and produces ultraviolet light. The phosphor coating then converts the ultraviolet light into visible light, allowing the bulb to produce light without blowing up.

2. How are fluorescent bulbs able to handle such high levels of electricity?

Fluorescent bulbs have a built-in mechanism called a ballast that regulates the flow of electricity. This helps to prevent the bulb from overheating and potentially exploding. The ballast also helps to provide a consistent flow of electricity, ensuring that the bulb produces a steady and reliable source of light.

3. Can fluorescent bulbs still explode under certain conditions?

While fluorescent bulbs are designed to withstand high levels of electricity, they can still explode under certain conditions. If the bulb is damaged or has a defect, it may not be able to handle the electricity and could explode. Additionally, if the bulb is exposed to extreme temperatures or excessive vibration, it could also potentially explode.

4. Are there any safety measures in place to prevent fluorescent bulbs from exploding?

Manufacturers of fluorescent bulbs are required to follow safety standards to ensure that their products are safe for consumers to use. This includes testing the bulbs to ensure they can handle the appropriate levels of electricity and implementing safety features such as the ballast. Additionally, it is important for individuals to handle and install fluorescent bulbs carefully to avoid damaging them and potentially causing them to explode.

5. What should I do if my fluorescent bulb does explode?

If a fluorescent bulb does explode, it is important to handle the situation carefully. Make sure to turn off the power and use gloves or a cloth to carefully remove any broken glass. Dispose of the broken bulb properly and replace it with a new one. It is also a good idea to check for any potential issues with the light fixture or wiring to ensure that the new bulb does not also explode.

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