- #1
Soren
- 10
- 0
I must be stupid but my textbook states that the refractive index of a media does not depend on the density according to the Lorentz-Lorenz formula (LL)
[tex] (\frac{n^2-1}{n^2+2}) = \frac{4\pi Ne^2}{ 3m} \frac{1}{\omega_0^2 \omega^2} [/tex]
Specifically it (Physical Optics, Akhmanov Nikitin pp.367) says: ".. since ρ ~ N, it follows from (LL formula) that the quantity
[tex] r =(\frac{n^2-1}{n^2+2}) \frac{1}{\rho}[/tex]
should not depend on density"
Are they simply telling me that ρ appears on both sides of the equation?
[tex] (\frac{n^2-1}{n^2+2}) = \frac{4\pi Ne^2}{ 3m} \frac{1}{\omega_0^2 \omega^2} [/tex]
Specifically it (Physical Optics, Akhmanov Nikitin pp.367) says: ".. since ρ ~ N, it follows from (LL formula) that the quantity
[tex] r =(\frac{n^2-1}{n^2+2}) \frac{1}{\rho}[/tex]
should not depend on density"
Are they simply telling me that ρ appears on both sides of the equation?