Why Does Integer Arithmetic in Haskell Seem Inconsistent?

In summary, integer arithmetic in Haskell involves manipulating and computing whole numbers using the built-in "Integer" data type and various functions and operators. Haskell also has a separate data type for floating-point numbers, but it is not as precise as integer arithmetic. The difference between "Integer" and "Int" is that the former can handle arbitrarily large integers while the latter has a fixed range. There are also libraries and packages available for integer arithmetic in Haskell, including ones for handling large integers.
  • #1
gnome
1,041
1
Can anybody explain what appear to be discrepancies in the way the following expressions are interpreted by Hugs (Haskell98 mode) ?

Code:
Main> div -6 4
ERROR - Cannot infer instance
*** Instance   : Num (b -> a -> a -> a)
*** Expression : div - fromInt 6 4

Main> div (-6) 4
-2
Main> -6 `div` 4
-1
Main> (-6) `div` 4
-2
 
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  • #2
Never mind.

I guess it must be right-associative, so -6 `div` 4 is interpreted as -(6 `div` 4).
 
  • #3



In Haskell, integer arithmetic follows the standard mathematical rules for division, where the result is rounded towards negative infinity. This means that when dividing negative numbers, the result will be rounded down, rather than up.

In the first expression, "div -6 4", the interpreter is unable to infer the type of the expression due to the use of the unary minus operator before the numbers. This is because the unary minus operator can have different meanings depending on the type of the operands. In this case, it is trying to interpret the expression as a function, which is not a valid instance for the Num type class.

In the second expression, "div (-6) 4", the parentheses around the first argument (-6) indicate that the unary minus operator should be applied to the number before passing it to the div function. This results in the correct answer of -2.

In the third expression, "-6 `div` 4", the backticks around the div operator indicate that it should be treated as an infix function. This means that the expression is evaluated as (-6) `div` 4, which again results in the correct answer of -2.

In the last expression, "(-6) `div` 4", the parentheses are unnecessary since the div operator already has higher precedence than the unary minus operator. However, including them does not change the result, since the expression is still evaluated as (-6) `div` 4.

Therefore, the apparent discrepancies in the way these expressions are interpreted by Hugs can be explained by the different ways in which the unary minus operator can be used in Haskell and the importance of parentheses and backticks in specifying the order of operations.
 

Related to Why Does Integer Arithmetic in Haskell Seem Inconsistent?

What is integer arithmetic in Haskell?

Integer arithmetic in Haskell refers to the manipulation and computation of whole numbers (integers) within the functional programming language Haskell. This includes basic arithmetic operations such as addition, subtraction, multiplication, and division, as well as more complex functions like modular arithmetic and bitwise operations.

How does Haskell handle integer arithmetic?

Haskell handles integer arithmetic using its built-in data type called "Integer". This type allows for arbitrarily large integers to be represented and computed, unlike other programming languages that have a fixed range for integer values. Additionally, Haskell has built-in functions and operators for integer arithmetic, making it convenient and efficient to use.

Can you use floating-point numbers in Haskell for arithmetic?

Yes, Haskell has a separate data type called "Float" for representing floating-point numbers. However, it is important to note that floating-point arithmetic in Haskell is not as precise as integer arithmetic, as it is subject to rounding errors and other limitations. Therefore, it is best to use floating-point numbers only when necessary and to be cautious when performing calculations with them.

What is the difference between "Integer" and "Int" in Haskell?

The "Integer" type in Haskell allows for arbitrarily large integers, while the "Int" type has a fixed range of values that it can represent. This means that the "Int" type is more efficient in terms of memory usage, but it is limited in the size of integers it can handle. The "Integer" type, on the other hand, can handle integers of any size, but it may be less efficient in terms of memory and performance.

Are there any libraries or packages for integer arithmetic in Haskell?

Yes, there are several libraries and packages available for integer arithmetic in Haskell, such as the "Arbitrary" and "Numeric" libraries. These libraries provide additional functions and operations for working with integers, and they can be easily imported and used in Haskell programs. Additionally, there are also libraries specifically for handling large integers, such as the "BigNum" package.

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