Why Does 238U Not Spontaneously Decay by Proton Emission

In summary: So 238U should decay by emitting a proton, but it doesn't. Why not?The absence of proton emission implies that the proton is more tightly bound in nuclei.
  • #1
sruthisupriya
33
0
why doesn't 238U decay spontaneously by emitting a proton?
 
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  • #2
Good question!

The principal modes of nuclear decay, particularly for heavy elements are gamma (EM), beta (electron) and alpha (2p,2n = 4He nucleus).

One could do a binding energy calculation to see which reaction, p or alpha emission, dumps the most energy, i.e. which one is more 'spontaneous'. One more readily observes photoneutron emission rather than photoproton emission.

The absence of proton emission implies that the proton is more tightly bound in nuclei.

Even spontaneous fission in some transuranic nuclei is preferred to proton emission.

Photoproton emission requires fairly high thresholds.
http://prola.aps.org/abstract/PRC/v44/i3/p1137_1
 
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  • #3
The reaction doesn't happen because it is prevented by energy concerns. In short, a proton and a Pa237 atom weigh more than a U238 atom:

Pa237: 237.0511

H1: 1.0078

Sum: 238.0589

compare to:

U238: 238.0508

Carl

[Edit: Thanks to Astronuc for pointing out that Pa237 should be used instead of U237.]
 
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  • #4
Ha, actually, it was the checking of neutron and proton driplines some years ago the thing that got me off from my mathematical cushions into pesky phenomenology. Empirically it can be seen that the stability line, where usual isotopes live, is exactly middle way between the proton and neutron driplines. This is, the number of protons you must remove from a stable isotope to make it neutron unstable is about the same that the number of protons you remove to drive it neutron unstable. Or something so. The moral is that long living atoms (as existing U atoms are) live far from the driplines.Ah, and obviously, the more neutrons you add, the more you escape from the proton dripline. So if U235 does not like proton decay, bet that U238 will not be better.
 
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  • #5
CarlB said:
The reaction doesn't happen because it is prevented by energy concerns. In short, a proton and a Pa237 atom weigh more than a U238 atom:

Pa237: 237.0511

H1: 1.0078

Sum: 238.0589

compare to:

U238: 238.0508

My favorite reaction, as for energy concerns it concerns, is Hg201 to alpha + Pt197 and then Pt197 decays beta. Someone should use it in a film script. Lot better than Davinci code stuff.

EDITED: Ok, Uranium fission gives us about 200 MeV, while here we get slightly a bit more than 1 MeV, and adding both reactions. But it is enough for a heater to work. :smile:
 
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  • #6
what r proton and neutron driplines?
 
  • #7
The proton dripline is where a proton heavy nucleus has too many protons to prevent another proton from binding to the nucleus. It's the limit to potential isotopes on the proton heavy side. The neutron dripline is similar to proton dripline, forming a limit to potential neutron heavy isotopes. I'm not really sure what limits neutrons from 'glomming' onto an already neutron heavy nucleus.

Hopefully someone can expand on my limited knowledge of the subject.
 
  • #8
Check the chart of nuclides, and look at which isotopes are stable. Too many or too few neutrons produces nuclei which decay to a more stable configuration.

http://www.nndc.bnl.gov/chart/

http://wwwndc.tokai-sc.jaea.go.jp/CN04/index.html

In particular, look at http://wwwndc.tokai-sc.jaea.go.jp/CN04/CN003.html

Ca-40 is the last stable nuclide for which P=N, where P = number of protons and N = number of neutrons.
 
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Related to Why Does 238U Not Spontaneously Decay by Proton Emission

1. Why doesn't 238U spontaneously decay by proton emission?

238U is a stable isotope, meaning that its nucleus is in a state of minimum energy and is not likely to undergo spontaneous decay. This is due to its large number of protons and neutrons, which create a strong nuclear force that holds the nucleus together.

2. Can 238U undergo proton emission under any circumstances?

Yes, 238U can undergo proton emission through a nuclear reaction called alpha decay. This occurs when the nucleus of 238U emits an alpha particle (two protons and two neutrons) and is transformed into a different element with a lower atomic number.

3. What is the difference between spontaneous proton emission and alpha decay?

Spontaneous proton emission refers to the natural decay of a radioactive nucleus, while alpha decay is a specific type of spontaneous decay where an alpha particle is emitted. Alpha decay is more common in heavier elements like 238U, while proton emission is more common in lighter elements.

4. Could there be any other factors preventing 238U from spontaneously decaying by proton emission?

Yes, other factors such as the shape and energy levels of the nucleus can also play a role in preventing spontaneous proton emission. The quantum mechanics of the nucleus can also affect the likelihood of certain types of decay occurring.

5. Is there any practical application for understanding why 238U does not spontaneously decay by proton emission?

Yes, understanding the mechanisms behind radioactive decay, including why certain elements decay in certain ways, is crucial for fields such as nuclear physics, nuclear energy, and radiometric dating. It also helps us better understand the fundamental properties of matter and the universe.

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