O yes! I thought the position is origin at t=0. So it will be 32-6=26 meters. Thanks. Is there any other way to do it ?phyzguy said:
Ok! By the way why we use area under the curve thing.kuruman said:
Yes.rudransh verma said:
The area under the curve represents the distance traveled by a particle over a certain period of time. This is because the curve is a graphical representation of the particle's velocity, and the area under the curve is equal to the product of velocity and time, which gives us the displacement.
In some cases, this method may work. However, it assumes that the particle is moving at a constant velocity, which is not always the case. Using the area under the curve method takes into account any changes in velocity and provides a more accurate measurement of displacement.
The shape of the curve directly affects the displacement calculation because it determines the velocity of the particle at any given time. A steeper curve indicates a higher velocity, while a flatter curve indicates a lower velocity. This variation in velocity is taken into account when calculating the area under the curve.
No, the area under the curve can be positive or negative, depending on the direction of the particle's motion. If the particle is moving in a positive direction, the area under the curve will be positive. If the particle is moving in a negative direction, the area under the curve will be negative.
Yes, the area under the curve can also be used to find other quantities such as velocity and acceleration. By taking the derivative of the curve, we can find the slope at any point, which represents the instantaneous velocity. And by taking the second derivative, we can find the rate of change of velocity, which represents the acceleration.