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an automobile, 30% owns a house, and 20% owns both an automobile and a house.

Calculate the probability that a person chosen at random owns an automobile or a house, but not

both.

I am Told that the answer is .5, I did this problem 2 different ways and I received different answers, and .5 is one of the answers.

If I draw a Venn Diagram I receive .5 and that makes sense.

I also tried this, \(P[A\cup B]=P[A]+P

**-P[A \cap B]\),**

I assume that I have something incorrect in the formula since I do not get the right answer. Would I be able to use this formula?

I assume that I have something incorrect in the formula since I do not get the right answer. Would I be able to use this formula?