Where does g force fit in this centripetal motion question?

In summary, the problem involves a car going around a vertical circle with a radius of 6 meters and a mass of 800kg. The goal is to determine the period of one cycle, given gravity is 9.8m/s^2 and the g-force is 6g. To solve this, the formula for net force (fnet=ma) is used, along with the equations for centripetal force (fn+fg=(mv^2)/r) and period (t=√4∏^2mr/fn+fg). The value of fn and fg will be in opposite directions, and since they are not equal, either fn or fg must be greater. At the bottom of the circle, the
  • #1
Henrybar
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a car goes around a vertical circle; determine the period of one cycle if the radius= 6m mass=800kg, gravity=9.8m/s^2 gforce = 6g

my attempt at the bottom of circle:
fnet=ma
fn+fg=(mv^2)/r
fn+fg=(4∏^2mr)/t^2
t=√4∏^2mr/fn+fg
t=√4∏^2(800)(6)/(fg+fg) <-----value of fn and fg will be in opposite directions

fn≠fg so either fn or fg has to be greater. If they both = mg at the bottom, do i multiply the gforce here? to which one? I originally thought that the g force would be multiplied to fn since there is acceleration towards the centre, but would that even make sense?
 
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  • #2
Henrybar said:
a car goes around a vertical circle; determine the period of one cycle if the radius= 6m mass=800kg, gravity=9.8m/s^2 gforce = 6g

my attempt at the bottom of circle:
fnet=ma
fn+fg=(mv^2)/r
fn+fg=(4∏^2mr)/t^2
t=√4∏^2mr/fn+fg
t=√4∏^2(800)(6)/(fg+fg) <-----value of fn and fg will be in opposite directions

fn≠fg so either fn or fg has to be greater. If they both = mg at the bottom, do i multiply the gforce here? to which one? why?

Lets break this problem into parts, first what's the radial acceleration?
 

Related to Where does g force fit in this centripetal motion question?

1. How does g force factor into centripetal motion?

The concept of g force is closely related to centripetal motion. G force, or gravitational force, is the force that pulls objects towards the center of the earth. In centripetal motion, an object is constantly changing direction, causing it to experience a force towards the center of rotation. This force is known as centripetal force and is equal to the object's mass multiplied by the square of its velocity divided by the radius of its circular path.

2. What is the relationship between g force and centripetal acceleration?

G force and centripetal acceleration are directly proportional to each other. As the magnitude of the centripetal force increases, so does the centripetal acceleration experienced by the object. This means that the greater the g force, the faster an object will change direction in its circular motion.

3. How does g force affect the motion of objects in a centrifuge?

In a centrifuge, objects are spun at high speeds to create a centrifugal force that separates components based on their density. The objects experience g force due to the centrifugal force acting on them. This g force can cause objects to move towards or away from the center of rotation, depending on their density and the speed of rotation.

4. Can g force be harmful to humans in centripetal motion?

Yes, g force can be harmful to humans in centripetal motion. As the magnitude of g force increases, the force on the human body also increases. This can lead to dizziness, nausea, and in extreme cases, loss of consciousness. Pilots, astronauts, and race car drivers undergo special training to withstand high levels of g force in their respective fields.

5. How does the radius of the circular path affect g force in centripetal motion?

The radius of the circular path has a direct impact on g force in centripetal motion. As the radius decreases, the magnitude of the g force increases. This is because the centripetal force is inversely proportional to the radius of the circular path. Therefore, the smaller the radius, the greater the force needed to keep an object in its circular motion, resulting in a higher g force experienced by the object.

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