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Homework Statement
Will the balancing condition get modified in Wheatstone bridge if AC source is used instead of a battery ?
clem said:No, but if you use a galvanometer (as is usual) as a detector, it wouldn't move.
You would need an AC meter, which probably woudn't be as sensitive as a galvanometer.
A Wheatstone Bridge is a type of electrical circuit that is used to measure unknown resistances. It consists of four resistors arranged in a diamond shape, with a voltage source connected across one diagonal and a galvanometer (a sensitive ammeter) connected across the other diagonal.
A Wheatstone Bridge works by balancing the resistances in the two sides of the diamond-shaped circuit. When the resistances are balanced, there is no current flow through the galvanometer, indicating that the unknown resistance is equal to a known resistance in the circuit.
The balancing condition in a Wheatstone Bridge is when the ratio of the two resistances on one side of the circuit is equal to the ratio of the two resistances on the other side. This results in no current flow through the galvanometer, indicating a balanced circuit.
An AC source can affect the balancing condition in a Wheatstone Bridge by introducing an additional phase difference between the two sides of the circuit. This can cause the circuit to be unbalanced, resulting in a small current flow through the galvanometer even when the resistances are theoretically balanced.
The effects of an AC source on the balancing condition can be minimized by using high-quality, low impedance resistors in the circuit and minimizing the length of the connecting wires. Additionally, using a higher frequency AC source can also reduce the impact on the balancing condition.