- #1
Prem1998
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- 13
We have,
e^(ix)=cosx+isinx
So, e^(i*i)=cosi+isini
Or e^-1=cosi+isini
Or 1/e + 0*i= cosi+isini
So, cosi=1/e and sini=0
But that's not the value of sin(i) that I found on the internet. These values are not even satisfying cos^2(x)+sin^2(x)=1.
What did I miss?
e^(ix)=cosx+isinx
So, e^(i*i)=cosi+isini
Or e^-1=cosi+isini
Or 1/e + 0*i= cosi+isini
So, cosi=1/e and sini=0
But that's not the value of sin(i) that I found on the internet. These values are not even satisfying cos^2(x)+sin^2(x)=1.
What did I miss?