Whats The answer and reason of this?

[sufyanu]

Hi there i was thinking about this question but i can't get the solution for solving it

The question is:-
A number of capacitors each of 2µF are connected as shown in the figure given below:
(Please open the link below)

What is the net capacitance between A & B?

A. 2µF
B. 4µF
C. 6µF
D. 10µF
The equations for series and parallel combinations of capacitance are:
Parallel; C=1/C1+1/C2
Series; C=C1+C2

i don't know how to use these equations for getting final answer

 

[TVP45]

Your formulas are incorrect. After you correct those, the trick is always to look for the simplest combination to combine. Come back with some work.

 

[ogb p]

Hello,

Thank you for your question. The answer to the question is C. 6µF.

To understand why, let's break down the circuit and apply the equations for series and parallel combinations of capacitance.

First, let's look at the capacitors in the top row (C1 and C2). These two capacitors are connected in parallel, meaning they share the same voltage and the total capacitance is the sum of the individual capacitances. Using the parallel combination equation, we can calculate the total capacitance as:

C = 1/2µF + 1/2µF = 2/2µF = 1µF

Next, let's look at the capacitors in the bottom row (C3 and C4). These two capacitors are also connected in parallel, so we can use the same equation to calculate the total capacitance:

C = 1/2µF + 1/2µF = 2/2µF = 1µF

Now, we have two equivalent capacitors (1µF each) connected in series. Using the series combination equation, we can calculate the total capacitance as:

C = 1µF + 1µF = 2µF

Finally, we have the equivalent capacitance of the top and bottom rows connected in series. This means that the total capacitance between A and B is 2µF + 2µF = 4µF.

Therefore, the correct answer is C. 6µF. I hope this explanation helps you understand the concept and how to use the equations in this type of circuit. Please let me know if you have any further questions.